numpy.bincount () in Python

Michael Zippo 18.07.2021

Around:
numpy.bincount (arr, weights = None, min_len = 0): in the + ve array of integers, it counts the occurrence of each element. Each bin value is an entry for its index. You can also set the size of the basket accordingly.
Parameters:

  arr:  [array_like, 1D] Input array, having positive numbers  weights:  [ array_like, optional] same shape as that of arr  min_len:  Minimum number of bins we want in the output array

Return:

 Output array with no. of occurrence of index value of bin in input - arr. Output array, by default is of the length max element of arr + 1.

Code 1: Working bincount () in NumPy

       # Python program explaining  
  # working method numpy.bincount ()  
   
   import   numpy as geek  
   
  # 1D array with + ve integers  
   array1   =   [  1  ,   6  ,   1  ,   1  ,   1  ,  < code class = "value"> 2  ,   2  ]  
   bin   =   geek.bincount (array1)  
   print   (  "Bincount output :"  ,   bin  ) 
   print   (  "size of bin:"   ,   len   (  bin  ),  " " ) 
    
   array2   =   [  1  ,   5  ,   5  ,   5  ,   4  ,   5  ,   5  ,   2  ,   2  ,   2  ] 
   bin   =   geek.bincount (array2) 
   print   ( " Bincount output : " ,   bin  ) 
   print   (  "size of bin:"  ,   len   (  bin  ),   ""  ) 
   
  # using min_length attribute  
   length   =   10  
   bin1   =   geek.bincount (array2,   None  , length) 
   print   (  "Bincount output :"  , bin1)  
   
   print   (  "size of bin:"  ,   len   (bin1),   ""  )

Exit :

 Bincount output: [0 4 2 0 0 0 1] size of bin: 7 Bincount output: [0 1 3 0 1 5] size of bin: 6 Bincount output: [0 1 3 0 1 5 0 0 0 0] size of bin: 10

Code 2: we can add according to the element using bincount ()

       # Python program explaining  
  # numpy.bincount () working method  
   
   import   numpy as geek  
   
  # 1D array with + ve integers  
   array2   =   [  10   ,   11  ,   4  ,   6  ,   2  ,   1  ,   9  ] 
   array1   =   [  1  ,   3  ,   1  ,   3  ,   1  ,   2  ,   2  ] 
   
  # array2: weight  
   bin   =   geek.bincount (array1, array2) 
   print   (  "Summation element-wise:"  ,   bin  ) 
   
  # Index 0: 0  
  # Index 1: 10 + 4 + 2 = 16  
  # Index 2: 1 + 9 = 10  
  # Index 3: 11 + 6 = 17

Output:

 Summation element-wise: [0. 16. 10. 17.]

Links:
https://docs.scipy.org/doc/numpy/reference/generated/numpy.bincount.html#numpy.bincount
,
This article is provided by Mohit Gupta_OMG

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