  # Python | Check if one list is a subset of another Method # 1: Using `all()`
` all () ` is used to check all elements of a container on one line. Checks all elements of one list for presence in another list.

 ` # Python3 demo code ` ` # check if the list is a subset of others ` ` # using all () `   ` # initializing list ` ` test_list ` ` = ` ` [` ` 9 ` `, ` ` 4 ` `, ` ` 5 ` `, ` ` 8 ` `, ` ` 10 ` `] ` ` sub_list ` ` = ` ` [` ` 10 ` `, ` ` 5 ` `, ` ` 4 ` `] `   ` # print original lists ` ` print ` ` (` ` " Original list: "` ` + ` ` str ` ` (test_list)) ` ` print ` ` (` ` "Original sub list:" + str (sub_list)) ``   # using all () for # check a subset list flag = 0 if ( all (x in test_list for x in sub_list)): flag = 1   # print result if (flag): print ( "Yes, list is subset of other." ) else : print ( "No, list is not subset of other." ) `

Output:

` Original list: [9, 4, 5, 8, 10] Original sub list: [10, 5, 4] Yes, list is subset of other. `

Method # 2: Using `set.issubset()`
The most used and recommended method for checking a sublist. This function is designed to perform a specific task of checking if one list is a subset of another.

 ` # Python3 demo code ` ` # check if the list is a subset of others ` ` # using issubset () ` ` `  ` # initializing list ` ` test_list ` ` = ` ` [` ` 9 ` `, ` ` 4 ` `, ` ` 5 ` `, 8 , 10 ] `` sub_list = [ 10 , 5 ]   # printing original lists print ( "Original list: " + str (test_list)) print ( "Original sub list:" + str (sub_list))   # using issubset () for # check a subset of the list flag = 0 if ( set (sub_list) .issubset ( set (test_list))): flag = 1   # print result if (flag): print ( "Yes, list is subset of other." ) else : print ( "No, list is not subset of other." ) `

Output:

` Original list: [9 , 4, 5, 8, 10] Original sub list: [10, 5] Yes, list is subset of other. `

Method # 3: Using `set.intersection()`
Another method dealing with sets, this method checks whether the intersection of both lists turns out to be a sublist that we are checking. This confirms that one list is a subset of the other.

 ` # Python3 demo code ` ` # check if the list is a subset of others ` ` # using intersection () `   ` # initializing list ` ` test_list ` ` = ` ` [` ` 9 ` `, ` ` 4 ` `, ` ` 5 ` `, ` ` 8 ` `, ` ` 10 ` `] ` ` sub_list ` ` = ` ` [` ` 10 ` `, ` ` 5 ` `] `   ` # printing original lists ` ` print ` ` (` `" Original list: "` ` + ` ` str ` ` (test_list)) ` ` print ` ` (` ` "Original sub list:" ` ` + ` ` str ` ` (sub_list)) `   ` # using intersection () for ` ` # check a subset of the list ` ` flag ` ` = ` ` 0 ` ` if ` ` ((` ` set ` ` (sub_list) & amp; ` ` set ` ` (test_list)) ` ` = ` ` = ` ` set ` ` (sub_list)): ` ` flag ` ` = ` ` 1 `   ` # print result ` ` if ` ` (flag): ` ` ` ` print ` ` (` ` "Yes, list is subset of other." ` `) ` ` else ` `: ` ` print ` ` (` `" No, list is not subset of other . "` `) `

Output:

` Original list : [9, 4, 5, 8, 10] Original sub list: [10, 5] Yes, list is a subset of other. `

Method # 4: Using iteration and counting

Using the number of items in both lists to check if the second list is a subset of the first list .

 ` # Python3 demo code ` ` # check if the list is a subset of others `   ` # Importing ` ` from ` ` collections ` ` import ` ` Counter `   ` def ` ` checkInFirst (a , b): ` ` # getting count ` ` count_a ` ` = ` ` Counter (a) ` ` ` ` count_b ` ` = ` ` Counter (b) `   ` # checking if element exists in the second list ` ` for ` ` key ` ` in ` ` count_b: ` ` if ` ` key ` ` not ` ` in ` ` count_a: ` ` return False `` if count_b [key] & gt; count_b [key]: return False return True   # initializing list a = [ 1 , 2 , 4 , 5 ] b = [ 1 , 2 , 3 ]   # Call function res = checkInFirst (a, b)   # Print list print ( "Original list:" + str (a)) print ( "Original sub list:" + str (b))   if res = = True : print ( " Yes, list is subset of other. " ) else : print ( "No, list is not subset of other. " )    # Added Paras Jain (anything is possible) `

Output:

` Original list: [1, 2, 4, 5] Original sub list: [1, 2, 3] No, list is not subset of other. `

Method # 5: Using a given index

 ` # Python3 demo code ` ` # check if the list is a subset of others `   ` # init list ` ` one ` ` = ` ` [` ` 1 ` `, ` ` 2 ` `, ` ` 3 ` `, ` ` 4 ` `, ` ` 5 ` `] ` ` two ` ` = ` ` [` ` 1 ` `, ` ` 2 ] ``   # using set to find if an item exists in another list result = set (x in one for x in two)   flag = 0   for ans in result: if ans = = False : flag = 1   # Print list print ( "Original list:" + str (one)) print ( "Original sub list:" + str (two))    if flag = = 0 :   print ( " Yes, list is subset of other . " ) else : print ( "No, list is not subset of other." )   # Added Paras Jain (anything is possible) `

Output:

` Original list: [1 , 2, 3, 4, 5] Original sub list: [1, 2] Yes, list is subset of other. `