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Most occurring number in a string using Regex in Python

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For a given string str , the challenge is to extract all the numbers from the string and figure out the most common element using Regex Python.

  • Guaranteed, that no two elements have the same frequency
    • Examples :
  Input:  geek55of55geeks4abc3dr2  Output:  55  Input:  abcd1def2high2bnasvd3vjhd44  Output:  2 

Approach: Extract all numbers from string str , using the re.findall () function from the regex library in python, and using the Counter function from the collection library we can get the most common element.

Below is an implementation of the above Python approach.

# your code goes here # Python program for
# find most common element

import re 

from collections import Counter 

 

def most_occr_element (word ):

 

# re.findall will extract all elements

# from a string and compose a list

arr = re.findall (r ’[0-9] +’ , word) 

 

# store set maximum frequency

maxm = 0  

 

# store the maxm element as often as possible

  max_elem = 0

  

# counter will store all numbers with

# their frequencies

# c = counter ((55, 2), (2, 1), (3, 1), (4, 1))

c = Counter (arr)

< code class = "undefined spaces">  

# Store all counter keys in a list in

# which first we would have our required element

for x in list (c.keys ()):

 

if c [x] & gt ; = maxm:

maxm = c [x]

max_elem = int (x)

 

return max_elem

  
# Driver program

if __name__ = = "__ main__"

word = ’geek55of55gee4ksabc3dr2x’

  print (most_occr_element (word))

Exit:

 55 

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