Line rjust () and ljust () in python ()

ljust | Python Methods and Functions

Syntax :

string.rjust (length, fillchar)

Parameters:

length: length of the modified string. If length is less than or equal to the length of the original string then original string is returned.
fillchar: (optional) characters which needs to be padded. If it's not provided, space is taken as a default argument.

after substituting a given character in left side of original string.

example

# Python demo program
# rjust ()

string = 'geeks'

length = 8

 
# If no fill character is specified, a space
# is used as a fill character

print (string.rjust (length))

Output:

 geeks 

example

# line example

string = 'geeks'

length = 8

fillchar = '*'

 

print (string.rjust (length, fillchar))

Output:

 *** geeks 

2. String chandeliers ()
The string ljust () method returns a new string of a given length after substituting the given character in the right side of the original string.

Syntax :

string.ljust (length, fillchar)

Parameters:

length: length of the modified string. If length is less than or equal to the length of the original string then original string is returned.
fillchar: (optional) characters which needs to be padded. If it's not provided, space is taken as a default argument.

after substituting a given character in right side of original string.

Example 1

# example string

string = 'geeks '

length = 8

 
# If no fill character is specified, a space
# used as padding character.

print (string.ljust ( length))

Output: (three samples la typed after geeks)

 geeks 

Example 2

# line example

string = 'geeks'

length = 8

fillchar = '*'

 
# display left alignment

print (string.ljust (length, fillchar))

Output:

 geeks *** 




Line rjust () and ljust () in python (): StackOverflow Questions

Answer #1

You can do this with str.ljust(width[, fillchar]):

Return the string left justified in a string of length width. Padding is done using the specified fillchar (default is a space). The original string is returned if width is less than len(s).

>>> "hi".ljust(10)
"hi        "

Answer #2

For many objects, you can use this code, replacing "object" with the object you"re interested in:

object_methods = [method_name for method_name in dir(object)
                  if callable(getattr(object, method_name))]

I discovered it at diveintopython.net (now archived). Hopefully, that should provide some further detail!

If you get an AttributeError, you can use this instead:

getattr( is intolerant of pandas style python3.6 abstract virtual sub-classes. This code does the same as above and ignores exceptions.

import pandas as pd
df = pd.DataFrame([[10, 20, 30], [100, 200, 300]],
                  columns=["foo", "bar", "baz"])
def get_methods(object, spacing=20):
  methodList = []
  for method_name in dir(object):
    try:
        if callable(getattr(object, method_name)):
            methodList.append(str(method_name))
    except:
        methodList.append(str(method_name))
  processFunc = (lambda s: " ".join(s.split())) or (lambda s: s)
  for method in methodList:
    try:
        print(str(method.ljust(spacing)) + " " +
              processFunc(str(getattr(object, method).__doc__)[0:90]))
    except:
        print(method.ljust(spacing) + " " + " getattr() failed")

get_methods(df["foo"])

Answer #3

a += [""] * (N - len(a))

or if you don"t want to change a in place

new_a = a + [""] * (N - len(a))

you can always create a subclass of list and call the method whatever you please

class MyList(list):
    def ljust(self, n, fillvalue=""):
        return self + [fillvalue] * (n - len(self))

a = MyList(["1"])
b = a.ljust(5, "")