# Python | List of different zipper sizes

Method # 1: Using ` enumerate () ` + loop
This is the way we use brute force to accomplish this particular task. In this process, we loop through both lists, and when one becomes larger than the other, we loop through the elements to start over from the beginning.

` `

` # Python3 demo code # archive of two different list sizes # using enumerate () + loop   # initializing lists test_list1 = [ 7 , 8 , 4 , 5 , 9 , 10 ] test_list2 = [ 1 , 5 , 6 ]   # printing original lists print ( "The original list 1 is:" + str (test_list1)) print ( "The original list 2 is:" + str (test_list2))   # using enumerate () + loop # archive of two different list sizes res = [] for i, j in enumerate (test_list1):   res.append ((j, test_list2 [i % len (test_list2)]))   # print result print ( " The zipped list is: " +   str (res )) `

` ` Exit:

` The original list 1 is: [7, 8, 4, 5, 9, 10] The original list 2 is : [1, 5, 6] The zipped list is: [(7, 1), (8, 5), (4, 6), (5, 1), (9, 5), (10, 6)] `

Method # 2: Using `itertools.cycle()`
This is another way to accomplish this particular task: in this loop we shorten the list so that it can start over from the beginning in case the smaller list is exhausted using the zip function.

Exit:

` The original list 1 is: [7, 8, 4, 5, 9, 10] The original list 2 is: [1, 5, 6] The zipped list is: [(7, 1), (8, 5), (4, 6), (5, 1), (9, 5), (10, 6)] `

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 ` # Python3 demo code ` ` # archive of two different list sizes ` ` # using itertools.cycle () ` ` from ` ` itertools ` ` import ` ` cycle `   ` # initializing lists ` ` test_list1 ` ` = [ 7 , 8 , 4 , 5 , 9 , 10 ] `` test_list2 = [ 1 , 5 , 6 ]   # print original lists print ( "The original list 1 is:" + str (test_list1)) print ( "The original list 2 is:" + str (test_list2))   # using itertools.cycle () # archive of two different list sizes res = list ( zip (test_list1, cycle (test_list2)) if len (test_list1)"  len (test_list2) else zip (cycle (test_list1), test_list2))   # print result print ( " The zipped list is: " +   str (res)) `