Examples :

  Input:  ([`a`,` apple`], [`b`,` ball`])  Output:  [`a`,` apple`, `b`,` ball`]  Input:  ([1, `sam`, 75], [2,` bob `, 39], [3,` Kate`, 87])  Output:  [1, `sam`, 75, 2,` bob`, 39, 3, `Kate`, 87]  
  Approach # 1:  Using reduce()
 
  reduce ()  — classic list operation, used to apply a specific function passed in its argument to all elements of the list In this case, we used the  add  function of the  operator  module which simply adds the given list arguments to an empty list. 
 
 
 
  
 
 
 
 
  # Python3 unpacking program  
  # tuple of lists  
 
  from   functools   import   reduce  
 
  import   operator 
 
  
 
  def   unpackTuple (tup):   
  
 
   return   (  reduce   (operator.add, tup))   
  
  # Driver code  
 
  tup   =   ([  `a`  ,   `apple`  ], [ ` b`  ,   `ball`  ])   
  print   (unpackTuple (tup)) 
 
  
 
   Exit :
 
 [`a`,` apple`, `b`,` ball`] 

  Approach # 2  Using Numpy [Alternative Approach # 1] 

   





  # Python3 unpacker  
  # tuple of lists  

  from   functools   import   reduce  
  import   numpy 
  
  def   unpackTuple (tup): 
  
   print   (  reduce   (numpy.append, tup)) 
  
  # Driver code  
  tup   =   ( [  `a`  ,  ` apple`  ], [ ` b`  ,   `ball`  ])  

  unpackTuple (tup) 




   Exit :
 [`a`` apple` `b`` ball`] 
  Approach # 3  Usage itertools.chain(*iterables)
  itertools.chain (* iterables)  creates an iterator that returns items from the first iteration until it is exhausted , then moves on to the next iteration until all iterations are exhausted. This makes our job much easier because we can simply add each iteration to an empty list and return it. 

  
   Exit :
 [`a`,` apple`, `b`,` ball`] 

        

        
        
        
        

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  # Python3 unpacker  
  # tuple of lists  
  from   itertools   import   chain 
  
  def   unpackTuple (tup): 
   res   =   [] 
   for   i   in   chain (  *   tup):  

   res.append (i) 
  
   print   (res) 
  
  # Driver code   
  tup   =   ([ ` a`  ,   `apple`  ], [  `b`  ,  ` ball`  ]) 
  unpackTuple (tup)