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Python | Unique vocabulary filter in the list

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Method: Using map () + set () + items () + sorted () + tuple ()

In this method we we simply combine functions to accomplish this task. The map function performs the task of extending the logic to all elements. The set function does the actual filtering on the pairs accessed by items () . The sorted function is required by the set to remove duplicates.

# Python3 code to demonstrate how it works
# Unique dictionary filter in the list
# Using map () + set () + items () + sorted () + tuple ()

 
# Initialize list

test_list = [{ ’gfg’ : 1 , ’is’ : 2 , ’best’ : 3 },

{ ’gfg’ : 1 , ’ is’ : 2 , ’best’ : 3 },

{ ’gfg’ : 9 , ’is’ : 8 , ’ best’ : 6 }] 

 
# print original list

print ( " The original list is: " + str (test_list))

 
# Unique dictionary filter in the list
# Using map () + set () + items () + sorted () + tuple ()

res = list ( map ( dict , set ( tuple ( sorted (sub.items ( ))) for sub in test_list)))

 
# print result

print ( "The list after removing duplicates : " + str (res))

Output:

The original list is: [ {’gfg’: 1, ’is’: 2, ’best’: 3}, {’gfg’: 1, ’is’: 2, ’best’: 3}, {’gfg’: 9, ’is’ : 8, ’best’: 6}]
The list after removing duplicates: [{’gfg’: 1, ’is’: 2,’ best ’: 3}, {’ gfg ’: 9,’ is ’: 8,’ best ’: 6}]

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