Method # 1: Using List Comprehension
This problem can be solved by using list comprehension, in this we check the list, and also by using string elements if we can find a match. and return true if we find one and false does not use conditional statements.
| # Python3 demo code
# check if the string contains a list item
# use comprehension list
# initialization string test_string = " There are 2 apples for 4 persons "
# initializing the test list test_list = [ ’apples’ , ’oranges’ ]
# print original line print ( "The original string:" + test_string)
# print the original list print ( "The original list:" + str (test_list))
# using comprehension list
# check if the string contains a list item res = [ele for ele in test_list if (ele in test_string)]
# print result print ( " Does string contain any list element: " + str ( bool (res))) |
Output:
The original string: There are 2 apples for 4 persons The original list: [’apples’,’ oranges ’] Does string contain any list element: True
Method # 2: using any()
Using any function is the most classic way in which you can accomplish this task, as well as efficiently. This function checks for a match in line with the match of each list item.
| # Python3 demo code
# check if string contains a list item
# use comprehension list
# initializing string test_string = "There are 2 apples for 4 persons"
# initialize the test list test_list = [ ’apples’ , ’ oranges ’ ]
# print original line print ( " The original string: " + test_string)
# print the original list print ( "The original list : " + str (test_list))
# using comprehension list
# check if the string contains a list item res = any (ele in < / code> test_string for ele in test_list)
# print result print ( " Does string contain any list element: " + str (res) |
Output:
The original string: There are 2 apples for 4 persons The original list: [’apples’,’ oranges’] Does string contain any list element: True
