Python String | rpartition ()

Syntax :

 string.rpartition (separator) 

Parameters :

  separator -  separates the string at the first occurrence of it. 

Return value:

1. It returns the part of the string before the separator , the delimiter parameter itself and the part after the delimiter if a delimiter parameter is found in the string.
2. It returns two blank lines followed by the given string if no delimiter is found in the string.

Exception :

 If separator argument is not supplied, it will throw TypeError. 

Code # 1:

# Python3 code explaining rpartition ()   # The line must be split string1 = "Geeks @ for @ Geeks @ is @ for @ geeks"   string2 = "Ram is not eating but Mohan is eating"   # Here & # 39; @ & # 39; - separator print (string1.rpartition ( ’@’ ))   # Here & # 39; is & # 39; is the delimiter print (string2.rpartition ( ’ is’ ))

Output:

 (’Geeks @ for @ Geeks @ is @ for’,’ @ ’,’ geeks’) (’Ram is not eating but Mohan ’,’ is’, ’eating’) 

Code # 2:

# Python3 code explaining rpartition ()   # The line must be split string = "Sita is going to school"   # Here “not” is a separator that is not # appears on this line print (string.rpartition ( ’not’ ))

Output:

 (’’, ’’, ’Sita is going to school’) 

Code # 3: TypeError

# Python3 code explaining TypeError # in rpartition ()   str = "Bruce Waine is Batman"   # Nothing is transferred as separator print ( str . rpartition ())

Output:

 Traceback (most recent call last): File "/home/e207c003f42055cf9697001645999d69.py", line 7, in print (str.rpartition ()) TypeError: rpartition () takes exactly one argument (0 given) 

Code # 4: ValueError

# Python3 code explaining ValueError # in rpartition ()   str = "Bruce Waine is Batman"   # Nothing is passed as separator print ( str . rpartition (""))

Exit d:

 Traceback (most recent call last): File "/home/c8d9719625793f2c8948542159719007.py", line 7, in print (str.rpartition ("")) ValueError: empty separator