Method # 1: Using index () and slicing a list
Slicing a list can be used to get sublists from a custom list, and the index function can be used to check an empty string that could potentially act as a delimiter. The downside to this is that it only works for one split, that is, it can split the list into only 2 lists.
| # Python3 demo code
# split the list into siblist on a separator
# using index () + slice the list
# initializing list test_list = [ ’Geeks’ , ’for’ ,’ ’,’ Geeks’, 1 , 2 ]
# print original list print ( "The original list:" + str (test_list))
# using index () + slice the list
# split the list into siblist delimited temp_idx = test_list.index (’ ’) res = [test_list [: temp_idx], test_list [temp_idx + 1 :]]
# print result print ( "The list of sublist after seperation:" + str (res)) |
Output:
The original list: [’Geeks’, ’for’, ”, ’Geeks’, 1, 2]
The list of sublist after seperation: [[’Geeks’, ’for’], [’Geeks’, 1, 2]]
Method # 2: Using itertools.groupby () + list comprehension
The problem of the above method can be solved by using the groupby function, which can divide by all the list breaks given by empty strings.
| # Python3 demo code
# split the list into siblist separator
# using itertools.groupby () + list comprehension from itertools import groupby
# initializing list test_list = [ ’Geeks’ ,’ ’,’ for ’, ’ ’, 4, 5, ’ ’, ’ Geeks’ , ’CS’ ,’ ’,’ Portal’]
# print original list pri nt ( "The original list:" + str (test_list))
# using itertools.groupby () + list comprehension
# split list into siblist separator res = [ list (sub) for ele, sub in groupby (test_list, key = bool ) if ele]
# print result print ( "The list of sublist after seperation:" + str (res)) |
Output:
The original list: [’Geeks’, ”, ’for’,”, 4, 5, ”, ’Geeks’, ’CS’,”, ’Portal’]
The list of sublist after seperation: [[’Geeks’], [’for’], [4, 5], [’Geeks’, ’CS’], [’Portal’]]
