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Python | Split a string into groups of n consecutive characters

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Examples :

`  Input:  str = "Geeksforgeeks", n = 3  Output:  [’Gee’ , ’ksf’,’ oor’, ’gee’,’ ks’]  Input:  str = "1234567891234567", n = 4  Output:  [1234, 5678, 9123 , 4567] `

Method # 1: Using List Comprehension

 ` # Python code to split a line ` ` # for every 3rd number `   ` # Initialization string ` ` string ` ` = ` ` "Geeksforgeeks" `   ` # Define the split point ` ` n ` ` = ` ` 3 `    ` # Using the comprehension list ` ` out ` ` = ` ` [(string [i: i ` ` + ` ` n]) ` ` for ` ` i ` ` in ` ` range ` ` (` ` 0 ` `, ` ` len ` ` (string), n)] `   ` # Printout ` ` print ` ` (out) `

Output:

` [’Gee’,’ ksf’, ’org’,’ eek’, ’s’] `

Method # 2: Using ` zip_longest `

 ` # Python code to split the number string ` ` # and the symbol in every 4th number `   ` # Import ` ` from ` ` itertools ` ` import ` ` zip_longest ` ` `  ` # Group function using zip_longest to split ` ` def ` ` group (n, iterable, fillvalue ` ` = ` ` None ` `): ` ` args ` ` = ` ` [` ` iter ` ` (iterable)] ` ` * ` ` n ` ` ` ` return ` ` zip_longest (fillvalue ` ` = ` ` fillvalue, ` ` * ` ` args) `   ` # Initialization string ` ` str ` ` = ` ` ’123GeeksForGeeks4567’ `   ` # Split Point ` ` n ` ` = ` ` 4 `   ` # list of separated lines ` ` out_string ` ` = ` ` [’` `’ .join (lis) for lis in group (n, str, ’` ` ’) ] `   ` # Initialize the output list ` ` out_no ` ` = ` ` [] `   ` # Convert a list of strings to a list of integers ` ` for ` ` a ` ` in ` ` out_string: ` ` out_no.append (a) `   ` # Print list ` ` print ` ` (out_no) `

Exit:

` [’123G’,’ eeks’, ’ForG’,’ eeks’, ’4567’] `