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Python | Split and pass the list as a separate parameter

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Method # 1: Using tuple()
This task can be accomplished with tuple () . This way we convert the list of pairs into a tuple and thus separate the individual elements as variables ready to be sent to the function.

# Python3 code to demonstrate how it works
# Split and pass the list as a separate parameter
# using tuple ()

 
# Helper function for demonstration

def pass_args (arg1, arg2):

print ( "The first argument is:" +   str (arg1))

  print ( "The second argument is:" +   str (arg2))

  
# initialize the list

test_list = [ 4 , 5 ]

 
# print original list

print ( " The original list is: " + str (test_list ))

 
# Split and pass the list as a separate parameter
# using tuple ()

one, two = tuple (test_list)

pass_args (one, two)

Output:

 The original list is: [4, 5] The first argument is: 4 The second argument is: 5 

Method # 2: Using * operator
Using the * operator is the most recommended method to accomplish this task. The * operator unpacks the double list into arguments and therefore solves our problem.

# Python3 code to demonstrate how it works
# Split and pass the list as a separate parameter
# using the * operator

  
# Helper function for demonstration

def pass_args (arg1, arg2):

print ( "The first argument is:" +   str (arg1))

print ( " The second argument is: " +   str (arg2))

 
# initialize the list

test_list = [ 4 , 5 ]

 
# print original list

print ( "The original list is:" + str (test_list))

 
# Split and pass the list as a separate parameter
# using the * operator

pass_args ( * test_list)

Output:

 The original list is: [4, 5] The first argument is: 4 The second argument is: 5 

Python | Split and pass the list as a separate parameter Python functions: Questions

Python | Split and pass the list as a separate parameter sep: Questions

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