  # Python | Shuffle two lists in the same order Method: Using the operator ` zip () + shuffle () ` + `*`
This method performs this task in three steps ... First, the lists are concatenated using ` zip () `. The next step is to execute shuffle with the built-in ` shuffle () ` and the last step is to unzip the lists to split the lists using the * operator.

 ` # Python3 code to demonstrate how it works ` ` # Shuffle two lists in the same order ` ` # Using zip () + * operator + shuffle () ` ` import ` ` random `   ` # initializing lists ` ` test_list1 ` ` = ` ` [` ` 6 ` ` , ` ` 4 ` `, ` ` 8 ` `, ` ` 9 ` `, ` ` 10 ` `] ` ` test_list2 ` ` = ` ` [` ` 1 ` `, ` ` 2 ` `, ` ` 3 ` `, ` ` 4 ` `, ` ` 5 ` `] `   ` # printing lists ` ` print ` ` (` `" The original list 1: "` ` + ` ` str ` ` (test_list1) ) ` ` print ` ` (` ` "The original list 2: "` ` + ` ` str (test_list2)) ``   # Shuffle two lists in the same order # Using zip () + * operator + shuffle () temp = list ( zip (test_list1, test_list2)) random.shuffle (temp) res1, res2 = zip ( * temp)   # Print result print ( "List 1 after shuffle:" + str ( list (res1))) print ( "List 2 after shuffle:" + str ( list (res2))) `

Output:

` The original list 1: [6, 4, 8, 9, 10] The original list 2: [1, 2, 3, 4, 5] List 1 after shuffle: [6, 10, 4, 8, 9] List 2 after shuffle: [1, 5, 2, 3, 4] `