Python | Returning the index of a sorted list

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Examples :

  Input:  [2, 3, 1, 4, 5]  Output:  [2 , 0, 1, 3, 4] After sorting list becomes [1, 2, 3, 4, 5] and their index as [2, 0, 1, 3, 4]  Input:  [6 , 4, 7, 8, 1]  Output:  [4, 1, 0, 2, 3] After sorting the list becomes [1, 4, 6, 7, 8] and their index as [ 4, 1, 0, 2, 3].

Method 1

import numpy

s = numpy.array ([ 2 , 3 , 1 , 4 , 5 ])

sort_index = numpy.argsort (s)

print (sort_index)

Output:

 [2, 0, 1, 3, 4]

Method 2

       s   =   [  2  ,   3  ,   1  ,   4  ,   5  ] 
   li   =   [] 
   
   for   i   in   range   (  len   (s)): 
     li.append ([s [i], i ]) 
   li.sort () 
   sort_index   =   [] 
   
   for   x   in   li:  
    sort_index.append (x [  1  ]) 
   
   print   (sort_index)

Output:

 [2, 0, 1, 3, 4]

Python | Returning the index of a sorted list

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