Method # 1: Using loop + remove () + startswith ()
Combining the above functions can solve this problem. In this, we remove elements that start with a specific prefix, available using a loop, and return the modified list.
| # Python3 demo code
# Remove prefix lines from the list
# using loop + remove () + starts with ()
# initialize the list test_list = [ ’xall’ , ’xlove’ , ’ gfg’ , ’xit’ , ’is’ , ’best’ ]
# print original list print ( "The original list:" + str (test_list))
# initialize prefix pref = ’x’
# Remove prefix strings from the list
# using loop + delete () + starts with () for word in test_list [:]: if word.startswith (pref): test_list.remove (word)
# print result print ( "List after removal of Kth character of each string:" + str (test_list)) |
Output:
The original list: [’xall’,’ xlove’, ’gfg’,’ xit’, ’is’,’ best’] List after removal of Kth character of each string: [’gfg’,’ is’, ’best’]
Method # 2: Using the comprehension list + startswith()
This is another a way to accomplish this task. However, we are not doing in-place deletion, instead we are re-creating the list with no elements matching the prefix.
| # Python3 code to demonstrate how it works
# Remove prefix lines from the list
# use comprehension list + startwith ()
# initialize the list test_list = [ ’xall’ , ’ xlove’ , ’gfg’ , ’xit’ , ’ is’ , ’be st’ ]
# print original list print ( "The original list:" + str (test_list))
# initialize prefix pref = ’x’
# Remove prefix strings from the list
# use comprehension list + startwith ( ) res = [ele for ele in test_list if not ele.startswith (pref )]
# print result print ( "List after removal of Kth character of each string:" + str (res)) |
Output:
The original list: [’xall’,’ xlove’, ’gfg’,’ xit’, ’is’,’ best’] List after removal of Kth character of each string: [’gfg’,’ is’, ’best’]
