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Python | Remove consecutive duplicates from the list

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Method # 1: Using groupby () + comprehension list
Using the groupby function, we can group the encountered elements as one and remove all duplicates in a row and just leave one element in the list.

# Python3 demo code
# removing consecutive duplicates
# using groupby () + list comprehension

from itertools import groupby 

 
# initializing list

test_list = [ 1 , 4 , 4 , 4 , 5 , 6 , 7 , 4 , 3 , 3 , 9 ]

 
# print original list

print ( "The original list is:" + str (test_list))

 
# using groupby ( ) + list comprehension
# removing consecutive duplicates

res = [i [ 0 ] for i in groupby (test_list)]

 
# print result

print ( "The list after removing consecutive duplicates:" +   str (res))

Exit:

 The original list is: [1, 4, 4, 4, 5, 6, 7, 4, 3, 3, 9] The list after removing consecutive duplicates: [1, 4, 5, 6, 7, 4, 3, 9] 

Method # 2: Using zip_ longest () + comprehension list
This function can be used to keep an element and remove subsequent elements using slicing. The zip_longest function performs the task of collecting values ​​in one list.

# Python3 demo code
# removing consecutive duplicates
# using zip_longest () + list comprehension

from itertools import zip_longest

 
# initializing list

test_list = [ 1 , 4 , 4 , 4 , 5 , 6 , 7 , 4 , 3 , 3 , 9 ]

 
# print original list

print ( "The original list is:" + str (test_list))

  
# using zip_longest () + comprehension list
# removing consecutive duplicates

res = [i for i, j in zip_longest (test_list, test_list [ 1 :])

if i! = j]

 
# print result

print ( "List after removing consecutive duplicates:" +   str (res))

Exit:

 The original list is: [1, 4, 4, 4, 5, 6, 7, 4, 3, 3, 9] List after removing consecutive duplicates: [1, 4, 5, 6, 7, 4, 3, 9] 

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