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# Python | Remove all values ​​from a list present in another list

Method # 1: Using List Comprehension
List Comprehension can be used to perform a naive method on only one line and therefore provides a simple method to accomplish this specific task.

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` # Python 3 demo code # remove items from another list # using comprehension list   # init list test_list = [ 1 , 3 , 4 , 6 , 7 ]   # initialize list removal remove_list = [ 3 , 6 ]   # print of the original list print ( "The original list is: " + str (test_list))   # print delete list print ( "The original list is:" +   str (remove_list))   # using a list comprehension to complete a task res = [i for i in test_list if i not in remove_list]   # print result print ( "The list after performing remove operation is:" + str (res)) Output: The original list is: [1, 3, 4, 6, 7] The original list is: [3, 6 ] The list after performing remove operation is: [1, 4, 7] Method # 2: Using filter () + lambda The filter function can be used in conjunction with a lambda expression to accomplish this task and create a new filtered list of all items that are not in the remove item list. # Python 3 demo code # remove items from another list # using a filter ( ) + lambda   # initializing list test_list = [ 1 , 3 , 4 , 6 , 7 ]   # initialize list removal remove_list = [ 3 , 6 ]   # print of the original list print ( "The original list is: " + str (test_list))  < br /> # print delete list print ( "The original list is:" + str (remove_list))   # using filter () + lambda to execute the task res = filter ( lambda i: i not in remove_list, test_list)    # print result print ( "The list after performing remove operation is:" + str (res)) `

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Output:

` The original list is: [1, 3 , 4, 6, 7] The original list is: [3, 6] The list after performing remove operation is: [1, 4, 7] `

Method # 3: Using `remove()`
` remove () ` can also perform this task, but only if the exception is not related to processing a specific element. You can iterate through all the elements of the delete list and remove those elements from the original list.

 ` # Python 3 demo code ` ` # remove items present in another list ` ` # using remove () `   ` # initializing list ` ` test_list ` ` = ` ` [` ` 1 ` `, ` ` 3 ` `, ` ` 4 ` `, ` ` 6 ` `, ` ` 7 ` `] `   ` # init remove list removal ` ` remove_list ` ` = ` ` [` ` 3 ` `, ` ` 6 ` ` ] `   ` # print original list ` ` print ` ` (` ` "The original list is:" ` ` + ` ` str ` ` (test_list)) `   ` # print delete list ` ` print ` ` (` ` "The original list is:" ` ` + ` ` str ` ` (remove_list)) ` ` `  ` # using remove () to complete the task ` ` # exceptions handled. ` ` for ` ` i ` ` in ` ` remove_list: ` ` try ` `: ` ` test_list.remove (i) ` ` except ` ` ValueError: ` ` pass `   ` # print result ` ` print ` ` (` ` "The list after performing remove operation is:" ` ` + ` ` str ` ` (test_list)) `

Output:

` The original list is: [1, 3, 4, 6, 7] The original list is: [3, 6] The list after performing remove operation is: [1, 4, 7 ] `