Python Regex: re.search () VS re.findall ()

Michael Zippo 18.07.2021

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Used to drop the special meaning of character following it (discussed below) [] Represent a character class ^ Matches the beginning $ Matches the end. Matches any character except newline? Matches zero or one occurrence. | Means OR (Matches with any of the characters separated by it. * Any number of occurrences (including 0 occurrences) + One ore more occurrences {} Indicate number of occurrences of a preceding RE to match. () Enclose a group of REs

research ()

re.search () either returns None (if the pattern does not match) or re.MatchObject which contains information about the corresponding part of the string. This method stops after the first match, so it is better suited for validating regular expressions than retrieving data.

Example :

       # Python program that demonstrates re.match ().  
   import   re 
  
  # Allows you to use a regular expression for date string matching  
  # as month name followed by day number  
   regex   =   r   "([a-zA-Z] +) (d +) " 
    
   match   =   re.search (regex,  " I was born on June 24 " ) 
  
   if   match!   =   None  :  
  
   # We reach here when the expression & quot; ([a-zA-Z] +) (/ d +) & quot;  
   # matches pages o date.  
  
   # This will print [14, 21) since it is at index 14  
   # and ends at 21.  
     print   (  "Match at index% s,% s"  %   (match.start (), match.end ())) 
    
   # We use the group () method to get all matches and  
     # captured groups. The groups contain matching values.  
   # Especially:  
   # match.group (0) always returns an exact match  
     # match.group (1) match.group (2), ... return capture  
   # groups in order from left to right in the input line  
   # match.group () is equivalent to match.group (0)  
  
   # This will print June 24  
   print   ( " Full match:% s " %   (match.group (  0  )))  
  
   # So this will print & quot; June & quot;  
   print   (  "Month:% s"  %   (match.group (  1  ))) 
   
  # So this will print & quot; 24 & quot;  
   print   (  "Day:% s"  %   (match.group (  2  ))) 
    
   else  :  
   print   (  "The regex pattern does not match. " )

Exit :

 Match at index 14, 21 Full match: June 24 Month: June Day: 24

re. findall ()

Return all non-overlapping pattern matches in a string as a list of strings. The string is scanned from left to right and matches are returned in that order.

Example :

# Python program for demonstrations
# find all ()

import re

# An example of a text string where the regular expression
# searched.

string = & quot; & quot; & quot; Hello my number is 123456789 and

my friend’s number is 987654321 & quot; & quot; & quot;

# An example of a regular expression for finding numbers.

regex = ’d +’

match = re.findall (regex, string)

print ( match)

Output:

 [’123456789’,’ 987654321’]

We hope this article has helped you to resolve the problem. Apart from Python Regex: re.search () VS re.findall (), check other code Python module-related topics.

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Davies Gonzalez

Warsaw | 2023-03-23

exp is always a bit confusing 😭 Python Regex: re.search () VS re.findall () is not the only problem I encountered. I am just not quite sure it is the best method

Davies Nickolson

Paris | 2023-03-23

Thanks for explaining! I was stuck with Python Regex: re.search () VS re.findall () for some hours, finally got it done 🤗. Will use it in my bachelor thesis

Boris Emmerson

Rome | 2023-03-23

Thanks for explaining! I was stuck with Python Regex: re.search () VS re.findall () for some hours, finally got it done 🤗. I just hope that will not emerge anymore