Python program to find your date of birth on the same day you were born

Michael Zippo

Examples :

Input: 1996-11-12
Output: [ ’1996-11-12’, ’2002-11-12’, ’2013-11-12’, ’2019-11-12’, ’2024-11-12’, ’2030-11-12’, ’2041 -11-12 ’,’ 2047-11-12 ’]

Input: 1992-11-2
Output: [’ 1992-11-2 ’,’ 1998-11-2 ’,’ 2009-11-2 ’,’ 2015-11-2 ’,’ 2020-11-2 ’,’ 2026-11-2 ’,’ 2037- 11-2 ’,’ 2043-11-2 ’,’ 2048-11-2 ’]

Recommended: please , try your approach on first before moving on to the solution.

Functions generated:

split_date (birthdate): this function splits the user-supplied date into year, month and day.
get_birthday (birthdate): this the function is used to return the day of the week the user was born.
true_birthdays (date of birth): this function is used to return a list of dates that have the same day of the week the user was born.

There are three methods to find birth dates that have the same day the user was born above. First, the user split_date () is the date, and split_date () will split the date into year, month and day. The get_birthday () function will then be used to find the day of the week for that particular date. Finally, true_birthdays () will be used to find a list of all dates that have the same day of the week. Inside this function, the for loop will iterate from year of birth to a specific year and will check if the date of birth is in any specific year with the same day of the week or not. If the day of the week is the same, then that date will be added to the list of dates.

Below is the implementation.

import datetime

import calendar

weekdays = [ "Monday" , "Tuesday" , "Wednesday" ,

"Thursday" , "Friday" , "Saturday" , "Sunday" ]

# get_birth day

def split_date ( birthday):

# Divide it by year, month and day

year, month, day = birthday.split ( ’-’ )

return year, month, day

def get_birthday (birthday):

year, month, day = split_date (birthday)

# Get the object’s birthday date

bdate = datetime.datetime ( int (year), int (month), int (day))

# Get the whole day of the week for the birthday

weekday = bdate .weekday ()

# Tell the user

day = weekdays [weekday]

return day

def listToString (x):

# initialize empty string

String = " "

< / p>

# returned string

return (String.join (x))

def true_birthdays (birthdate):

year, month, day = split_date (birthdate)

# get the year from birthday

year = birthdate [: 4 ]. split ( ’-’ )

   
   # convert list to string  
   year   =   listToString (year) 
   
   # get weekday birthday  
   d_day   =   get_birthday (birthdate) 
   
   # list of true date of birth [birthday with the same  
   # weekday as your birthday]  
   true_BD   =   [] 
   
   j   =   0  
    
     for   i   in   range   (  int   (year),   2050  ): 
   
   # add + j to the year of birth  
   new_year   =   int   (year)   +   j 
   
     # build a new birthday  
   new_birthday   =   str   (  str   (new_year)   +   "-"   +   month   +   "-"   +   day) 
   
   # get weekday new birthday  
   new_d_day   =   get_birthday (new_birthday)  
   
   # if birthday has a day of the week  
   # like the day you were born  
   if   d_day   =   =   new_d_day: 
   
     # add true date of birth to list  
   true_BD.append (new_birthday) 
   else  : 
   pass  
   j   +   =   1  
   
   return   true_BD 
    
    
   def   main (): 
   
   # Get date of birth  
   birthdate   =   "1996-11-12" 
   
   # year_limit = input (& quot; search limit since your birthday- & quot;)  
     dates  < code class = "keyword"> =   true_birthdays (birthdate) 
   
   print   (dates)  
   
   
  # Code driver  
  main ()

Exit:

[’1996-11-12’, ’2002-11-12’, ’2013-11-12 ’,’ 2019-11-12 ’,’ 2024-11-12 ’,’ 2030-11-12 ’,’ 2041-11-12 ’,’ 2047-11-12 ’]

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Python program to find your date of birth on the same day you were born

Recommended: please , try your approach on first before moving on to the solution.

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