Examples :

  Input:  limit = 1, diff = 0.5  Output:  [-1, -0.5 , 0.0, 0.5, 1] ​​ Input:  limit = 25, diff = 5  Output:  [-25, -20, -15, -10, -5, 0, 5, 10, 15, 20, 25] 

Approach # 1: The naive approach

This is the naive approach to the above problem. First, create an empty list & # 39; lst & # 39; and then we use a while loop to add the next integer with a difference of & # 39; diff & # 39 ;.

# Python3 conversion program # list to dictionary   def create (limit, diff):   lst = [ - limit] while lst [ - 1 ] & lt; limit: lst.append (lst [ - 1 ] + diff) lst [ - 1 ] = limit return lst   # Driver code limit = 1 diff = 0.5 print (create (limit, diff))

Exit:

 [-1, -0.5, 0.0, 0.5, 1] ​​ 

  Approach # 2  Using Python Numpy 
 Using the Numpy module makes the solution much easier. In this method we use  np.arange  which returns evenly spaced values ​​in a given interval & # 39; diff & # 39 ;. 

  




   
  # Python3 conversion program  
  # list to dictionary  
  import   numpy as np 
  
  def   create (limit, diff): 
   lst   =   np.arange (diff, limit , diff) 
   if   (lst [  -   1  ]!   =   limit): 
    lst   =   np.r_ [lst, limit] 
  
   return   np.r_ [  -   lst [::   -   1  ],   0  , lst ] .tolist () 
  
  # Driver code   
  limit   =   1  
  diff   =   0.5  
  print   (create (limit, diff)) 



  
  Exit:
 [-1, -0.5, 0.0, 0.5, 1] ​​