Examples :
Input: The quick brown fox jumps over the lazy dog Output: Yes Input: abcdefgxyz Output: No
We have already discussed the naive approach to checking pangrams in this article . Now let’s discuss a Pythonic approach to do the same.
Approach # 1: Pythonic Naive
This method uses a loop to check if each character in the string belongs to alphabet set or not.
| # Python3 program for
# Check if the string is a pangram import string def ispangram ( str ): alphabet = "abcdefghijklmnopqrstuvwxyz" for char in alphabet: if char not in str . lower (): return False return True
# Driver code string = ’ the quick brown fox jumps over the lazy dog’ if (ispangram (string) = = True ): print ( "Yes" ) else : print ( "No" ) |
Exit:
Yes
Approach # 2 Using Python Set
Convert the given string to a set and then check if the alphabets are greater or equal or not. If the rowset is greater than or equal to, print "Yes", otherwise "No".
| # Python3 program for
# Check if the string is a pangram import string alphabet = set (string.ascii_lowercase) def ispangram (string): return set (string.lower ( ))" = alphabet
# Driver code string = " The quick brown fox jumps over the lazy dog " if (ispangram (string) = = True ): print ( "Yes" ) else : print ( "No" ) |
Exit :
Yes
Approach # 3: An alternative to a given method
This is another method that is used uses the Python suite to determine if a string is a pangram or not. We compose a set of lowercase alphabets and a given string. If a set of a given string is subtracted from a set of alphabets, we know if the string is a pangram or not.
| # Python3 program for
# Check if the string is a pangram import string alphabet = set (string.ascii_lowercase) def ispangram ( str ): return not set (alphabet) < / code> - set ( str )
# Driver code string = ’the quick brown fox jumps over the lazy dog’ if (ispangram (string) = = True ): print ( "Yes" ) else : print ( "No" ) |
Output:
Yes
Approach # 4: ASCII method
Check if each character in the string is in the ASCII lowercase range, i.e. from 96 to 122.
| # Python3 program for
# Check if the string is a pangram import itertools import string alphabet = set (string.ascii_lowercase) def ispangram ( str ): return sum ( 1 for i in set ( str ) if 96 & lt; ord (i) " = 122 ) = = 26
# Driver code string = ’the quick brown fox jumps over the lazy dog’ if (ispangram (string) = = True ): print ( "Yes" ) else : print ( "No" ) |
Exit :
Yes
