TimedeltaIndex.argmin() Pandas TimedeltaIndex.argmin() returns the indices of the minimum values ​​along the axis in the object TimedeltaIndex. The function is similar to numpy.ndarray.argmin .

Syntax: TimedeltaIndex.argmin (axis = None, * args, ** kwargs)

Parameters:
axis: None

Return: integer index value

Example # 1: Use TimedeltaIndex.argmin () to find the indices of the minimum value in a given TimedeltaIndex.

# import pandas as pd import pandas as pd   # Create first TimedeltaIndex tidx = pd.TimedeltaIndex (start = `1 days 02: 00: 12.00 1124` , periods = 5 , freq = `N` , name = `Koala` )    # Print the TimedeltaIndex object print (tidx)

Output:

We will now print the index of the minimum value in the tidx object.

# return the index of the minimum value readings. tidx.argmin ()

Output:

How we see in the output that TimedeltaIndex.argmin () is 0, which indicates that the minimum value in the tidx object is at index 0.

Example # 2: Use TimedeltaIndex.argmin () to find the indices of the minimum value in a given TimedeltaIndex.

# pandas import as pd import pandas as pd   # Create TimedeltaIndex object tidx = pd.TimedeltaInde x (data = [ `22 days 2 min 3us 10ns` , `1 days 06:05 : 01.000030` ,  `- 1 days + 23: 59: 59.999999` ])   # Print the TimedeltaIndex object print (tidx)

Output:

We will now print the index of the minimum value in the tidx object.

# return index minimum value. tidx.argmin ()

Output:

As we can see in the output, TimedeltaIndex.argmin () is 2, indicating that the minimum value in the tidx object is present at the second index.