Series.lt() is used to compare two rows and return a boolean value for each matching item.
Syntax: Series.lt (other, level = None, fill_value = None, axis = 0)
other: b> other series to be compared with
level: int or name of level in case of multi level
fill_value: Value to be replaced instead of NaN
axis: 0 or `index` to apply method by rows and 1 or `columns` to apply by columns.
Return type: b> Boolean series
Note: results are returned based on a comparison of the calling series & lt; other series.
To load the dataset used in the following example, click here.
In the following examples, the data frame being used contains data some NBA players. An image of the data frame before any operations is attached below.
Example # 1:
This example compares the Age and Weight columns using the .lt () method. Since the values in the weight columns are very large compared to the age column, therefore, the values are divisible by 10 first. The .dropna () method removes null rows before comparison to avoid errors.
As shown in the output image, the new column is True, where the value in the Age column is less, than Weight / 10.
Example # 2: Handling values NaN
In this example, two series are created using
pd.Series () . The series also contains a value of zero and therefore 10 is passed to the fill_value parameter to replace the zero values with 10. p>
As you can see from the results, the NaN values have been replaced with 5 and the comparison is done after the replacement, and the new values are used for comparison.
0 True 1 False 2 False 3 False 4 False 5 True 6 False 7 False 8 True dtype: bool