series.le() is used to compare each item in a Caller series against a skipped series. It returns True for every element that is less than or equal to an element in the passed series.
Note: results are returned based on series comparison of callers & lt; = other series.
Syntax: Series.le (other, level = None, fill_value = None, axis = 0) p >
other: other series to be compared with
level: int or name of level in case of multi level
fill_value: Value to be replaced instead of NaN
axis: 0 or `index` to apply method by rows and 1 or `columns` to apply by columns.
Return type: Boolean series
Example # 1: NaN handling
In this example, two series are created using
pd.Series () . The series contains several zero values and several equal values with the same indices. The series are compared using the
le () method and 10 is passed to the fill_value parameter to replace the NaN values with 10.
Output: b >
As shown in the output, True was returned wherever the value in the caller row was less than or equal to the value in the passed row. You can also see that the zero values have been replaced with 10 and the comparison has been done using that value.
Example # 2: Calling Series with str objects p>
In this example, two series are created using Output:
pd.Series () . The series also contains some string values. In the case of strings, the comparison is performed against their
# pandas module import
pandas as pd
# numpy module import
numpy as np
# create series 1
# create episode 2
# NaN replacement
# call and return to the result variable
series1.le (series2, fill_value
As you can see from the output, in the case of strings, the comparison was performed using their ASCII values.