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Series.clip_lower() is used for
Series.clip_lower() values ‚Äã‚Äãbelow the passed smallest value. A threshold value is passed as a parameter, and all values ‚Äã‚Äãin the sequence that are less than the threshold values ‚Äã‚Äãbecome equal to it.
Syntax: Series.clip_lower (threshold, axis = None , inplace = False)
threshold: numeric or list like, Sets minimum threshold value and in case of list, sets separate threshold values ‚Äã‚Äãfor each value in caller series (Given list size is same)
axis: 0 or ’index’ to apply method by rows and 1 or ’columns’ to apply by columns
inplace: Make changes in the caller series itself. (Overwrite with new values)
Return type: Series with updated values ‚Äã‚Äã
To load the dataset used in the following example, click here.
In the following examples, the data frame used contains data for some NBA players. An image of the data frame before any operations is attached below.
Example # 1 : Applied to single value series p>
In this example, a minimum threshold of 26 is passed as a parameter to the .clip_lower () method. This method is called on the Age column of the data frame, and the new values ‚Äã‚Äãare stored in the Age_new column. Before performing any operations, null lines are removed using .dropna ()
As shown in the output image, the minimum value of the Age_new column is 26. All values ‚Äã‚Äãless than 26 have been increased to 26 and saved as a new th column.
Example # 2: Applied to series with a list type value
In this example, the first 10 rows of the Age column are retrieved and stored using the .head () method. After that, a list of the same length is created, which is passed to the threshold parameter of the .clip_lower () method to set a separate threshold value for each value in the series. The returned values ‚Äã‚Äãare stored in a new column "clipped_values".
As display But on the output image, each value in the sequence had a different threshold value according to the passed list, and therefore results were returned according to the separate threshold value of each item.
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Python | Pandas Series.clip_lower () clip: Questions
How do I copy a string to the clipboard?
I"m trying to make a basic Windows application that builds a string out of user input and then adds it to the clipboard. How do I copy a string to the clipboard using Python?
ctypes seem to be an overkill for this simple task.
Tkinter is a cross-platform GUI framework, which ships with Python by default and has clipboard accessing methods along with other cool stuff.
If all you need is to put some text to system clipboard, this will do it:
from Tkinter import Tk r = Tk() r.withdraw() r.clipboard_clear() r.clipboard_append("i can has clipboardz?") r.update() # now it stays on the clipboard after the window is closed r.destroy()
And that"s all, no need to mess around with platform-specific third-party libraries.
If you are using Python 3, replace
Python | Pandas Series.clip_lower () clip: Questions
Python script to copy text to clipboard
I just need a python script that copies text to the clipboard.
After the script gets executed i need the output of the text to be pasted to another source. Is it possible to write a python script that does this job?
Finding the index of an item in a list
Given a list
["foo", "bar", "baz"] and an item in the list
"bar", how do I get its index (
1) in Python?
>>> ["foo", "bar", "baz"].index("bar") 1
Reference: Data Structures > More on Lists
Note that while this is perhaps the cleanest way to answer the question as asked,
index is a rather weak component of the
list API, and I can"t remember the last time I used it in anger. It"s been pointed out to me in the comments that because this answer is heavily referenced, it should be made more complete. Some caveats about
list.index follow. It is probably worth initially taking a look at the documentation for it:
list.index(x[, start[, end]])
Return zero-based index in the list of the first item whose value is equal to x. Raises a
ValueErrorif there is no such item.
The optional arguments start and end are interpreted as in the slice notation and are used to limit the search to a particular subsequence of the list. The returned index is computed relative to the beginning of the full sequence rather than the start argument.
Linear time-complexity in list length
index call checks every element of the list in order, until it finds a match. If your list is long, and you don"t know roughly where in the list it occurs, this search could become a bottleneck. In that case, you should consider a different data structure. Note that if you know roughly where to find the match, you can give
index a hint. For instance, in this snippet,
l.index(999_999, 999_990, 1_000_000) is roughly five orders of magnitude faster than straight
l.index(999_999), because the former only has to search 10 entries, while the latter searches a million:
>>> import timeit >>> timeit.timeit("l.index(999_999)", setup="l = list(range(0, 1_000_000))", number=1000) 9.356267921015387 >>> timeit.timeit("l.index(999_999, 999_990, 1_000_000)", setup="l = list(range(0, 1_000_000))", number=1000) 0.0004404920036904514
Only returns the index of the first match to its argument
A call to
index searches through the list in order until it finds a match, and stops there. If you expect to need indices of more matches, you should use a list comprehension, or generator expression.
>>> [1, 1].index(1) 0 >>> [i for i, e in enumerate([1, 2, 1]) if e == 1] [0, 2] >>> g = (i for i, e in enumerate([1, 2, 1]) if e == 1) >>> next(g) 0 >>> next(g) 2
Most places where I once would have used
index, I now use a list comprehension or generator expression because they"re more generalizable. So if you"re considering reaching for
index, take a look at these excellent Python features.
Throws if element not present in list
A call to
index results in a
ValueError if the item"s not present.
>>> [1, 1].index(2) Traceback (most recent call last): File "<stdin>", line 1, in <module> ValueError: 2 is not in list
If the item might not be present in the list, you should either
- Check for it first with
item in my_list(clean, readable approach), or
- Wrap the
indexcall in a
try/exceptblock which catches
ValueError(probably faster, at least when the list to search is long, and the item is usually present.)
One thing that is really helpful in learning Python is to use the interactive help function:
>>> help(["foo", "bar", "baz"]) Help on list object: class list(object) ... | | index(...) | L.index(value, [start, [stop]]) -> integer -- return first index of value |
which will often lead you to the method you are looking for.
The majority of answers explain how to find a single index, but their methods do not return multiple indexes if the item is in the list multiple times. Use
for i, j in enumerate(["foo", "bar", "baz"]): if j == "bar": print(i)
index() function only returns the first occurrence, while
enumerate() returns all occurrences.
As a list comprehension:
[i for i, j in enumerate(["foo", "bar", "baz"]) if j == "bar"]
Here"s also another small solution with
itertools.count() (which is pretty much the same approach as enumerate):
from itertools import izip as zip, count # izip for maximum efficiency [i for i, j in zip(count(), ["foo", "bar", "baz"]) if j == "bar"]
This is more efficient for larger lists than using
$ python -m timeit -s "from itertools import izip as zip, count" "[i for i, j in zip(count(), ["foo", "bar", "baz"]*500) if j == "bar"]" 10000 loops, best of 3: 174 usec per loop $ python -m timeit "[i for i, j in enumerate(["foo", "bar", "baz"]*500) if j == "bar"]" 10000 loops, best of 3: 196 usec per loop