Python | Pandas Series.abs ()

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Series.abs() Pandas Series.abs() is used to get the absolute numeric value of each item in Series / DataFrame.

Syntax: Series.abs()

Parameters: No parameters

Returns: Return the Series or DataFrame containing the absolute value of each element.

Code # 1:

# pandas module import

import pandas as pd


# create lists

lst = [ 2 , - 10.87 , - 3.14 , 0.12 ]

lst2 = [ - 10.87 + 4j ]

ser = pd.Series (lst)

ser1 = pd.Series (lst2)


# print values ‚Äã‚Äãexplaining abs ()

print (ser1. abs (), ’’ , ser. abs ())

Exit:

 0 11.582612 dtype : float64 0 2.00 1 10.87 2 3.14 3 0.12 dtype: float64 

Code # 2: Explanation of using abs () on a specific line

Exit :

 Name Age val ope 0 John 31 98 11 1 Hari 29 48 39 2 Peter 57 -80 167 3 Loani 40 -14 101 

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Python | Pandas Series.abs () absolute: Questions

How to get an absolute file path in Python

3 answers

izb By izb

Given a path such as "mydir/myfile.txt", how do I find the file"s absolute path relative to the current working directory in Python? E.g. on Windows, I might end up with:

"C:/example/cwd/mydir/myfile.txt"
877

Answer #1

>>> import os
>>> os.path.abspath("mydir/myfile.txt")
"C:/example/cwd/mydir/myfile.txt"

Also works if it is already an absolute path:

>>> import os
>>> os.path.abspath("C:/example/cwd/mydir/myfile.txt")
"C:/example/cwd/mydir/myfile.txt"

Python | Pandas Series.abs () absolute: Questions

How to check if a path is absolute path or relative path in a cross-platform way with Python?

3 answers

UNIX absolute path starts with "/", whereas Windows starts with alphabet "C:" or "". Does python have a standard function to check if a path is absolute or relative?

175

Answer #1

os.path.isabs returns True if the path is absolute, False if not. The documentation says it works in windows (I can confirm it works in Linux personally).

os.path.isabs(my_path)

Python | Pandas Series.abs () absolute: Questions

How to join absolute and relative urls?

3 answers

I have two urls:

url1 = "http://127.0.0.1/test1/test2/test3/test5.xml"
url2 = "../../test4/test6.xml"

How can I get an absolute url for url2?

139

Answer #1

You should use urlparse.urljoin :

>>> import urlparse
>>> urlparse.urljoin(url1, url2)
"http://127.0.0.1/test1/test4/test6.xml"

With Python 3 (where urlparse is renamed to urllib.parse) you could use it as follow:

>>> import urllib.parse
>>> urllib.parse.urljoin(url1, url2)
"http://127.0.0.1/test1/test4/test6.xml"

We hope this article has helped you to resolve the problem. Apart from Python | Pandas Series.abs (), check other absolute-related topics.

Want to excel in Python? See our review of the best Python online courses 2023. If you are interested in Data Science, check also how to learn programming in R.

By the way, this material is also available in other languages:



Anna Schteiner

Boston | 2023-01-29

Thanks for explaining! I was stuck with Python | Pandas Series.abs () for some hours, finally got it done 🤗. I am just not quite sure it is the best method

Carlo Lehnman

Massachussetts | 2023-01-29

I was preparing for my coding interview, thanks for clarifying this - Python | Pandas Series.abs () in Python is not the simplest one. Will use it in my bachelor thesis

Marie Williams

Rome | 2023-01-29

Thanks for explaining! I was stuck with Python | Pandas Series.abs () for some hours, finally got it done 🤗. I am just not quite sure it is the best method

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# pandas module import

import pandas as pd

df = pd.DataFrame ({ ’Name’ : [ ’John’ , ’ Hari’ , ’Peter’ , ’Loani’ ],

’Age’ : [ 31 , 29 , 57 , 40 ],

’val’ : [ 98 , 48 , - 80 , - 14 ]})

df [ ’ope’ ] = (df.val - 87 ). abs ()


df