 # Python | Numpy numpy.ndarray .__ pos __ ()

Using the numpy.ndarray .__ pos __ () method Numpy, , you can multiply each and every element of the array with 1. Therefore, the resulting array having the following value is same as the original array.

Syntax: ndarray .__ pos __ (\$ self, /)

Return : + self

Example # 1:
In this example, we see that after applying ` numpy .__ pos __ () ` we get a simple array, which can be the same as the original one.

 ` # import important module in python ` ` import ` ` numpy as np `   ` # make an array with NumPy ` ` gfg ` ` = ` np.array ([ ` 1 ` `, ` ` - ` ` 2 ` `, ` ` 3 ` `, ` ` 4 ` `, ` ` 5 ` `, ` ` 6 ` `]) `   ` # applying the numpy method .__ pos __ () ` ` print ` ` (gfg .__ pos __ ()) `

Output:

` [1 -2 3 4 5 6] `

Example # 2:

 ` # import important module in python ` ` import ` ` numpy as np ` < code class = "undefined spaces">   ` # make an array with NumPy ` ` gfg ` ` = ` ` np.array ([[` ` 1 ` `, ` ` 2 ` `, ` ` - ` ` 3 ` `, ` ` 4 ` `, 5 , 6 ], ```` ```` [ - 6 , 5 , 4 , 3 , 2 , - < code class = "value"> 1 ` `]]) `   ` # applying the numpy method .__ pos __ () ` ` print ` ` (gfg .__ pos __ ()) `

Exit:

` [[1 2 -3 4 5 6] [-6 5 4 3 2 -1]] `