 # Python | Numpy numpy.ndarray .__ le __ ()

With the numpy.ndarray .__ le __ () method Numpy , we can determine which element of the array is less than or equals to the value specified in the parameter. It will return you an empty boolean array with only True and False values.

Syntax: ndarray .__ le __ (\$ self, value, /)

Return: self & lt; = value

Example # 1:
In this example, we can see that after applying ` numpy .__ le __ () `, we get a simple boolean array that can tell us which element in the array is less than or equal to an element of the supplied parameter.

 ` # import important module in python ` ` import ` ` numpy as np `   ` # make an array with NumPy ` ` gfg ` ` = ` ` np.array ([` ` 1 ` `, ` ` 2 ` `, ` ` 3 ` `, ` ` 4 ` `, 5 , 6 ]) ````   # applying the numpy method .__ le __ () print (gfg .__ le __ ( 4 )) ```

Output:

` [True True True True False False] `

Example # 2:

` `

``` # import important module into python import numpy as np    # make an array with NumPy gfg = np.array ([[ 1 , 2 , 3 , 4 , 5 , 6 ], [ 6 , 5 , 4 , 3 , 2 , 1 ]])    # applying the numpy method .__ le __ () print (gfg .__ le __ ( 4 )) ```

` ` Exit:

` [[True True True False False] [ False False True True True True]] `