Python | Numpy numpy.matrix.any ()

With the Numpy numpy.matrix.any () method, we can compare each element of one matrix to another, or we can provide the axis on which we want to apply the comparison if any element matches this it returns true

Syntax: numpy.matrix.any()

Return: Return true if any match found else false

Example # 1:
In this example, we see that using the matrix.any () method we can compare any two matrices that have different sizes, and if matrix.any () any match, return true.

# import important module into python

import numpy as np

 
# make a matrix with NumPy

gfg1 = np.matrix ( `[1, 2, 3, 4]` )

gfg2 = np.matrix ( `[1, 2]` )

 
# using the matrix.any () method

geeks = (gfg1 = = gfg2). any ()

 

print (geeks)

Exit:

 True 

Pr Number 2:

# import important module into python

import numpy as np

 
# make a matrix with NumPy

gfg1 = np.matrix ( ` [1, 2, 3; 4, 5, 6; 7, 8, 9] ` )

gfg2 = np.matrix ( ` [1, 2, 3] ` )

  
# using the matrix.any () method

geeks = (gfg1 = = gfg2). any ()

 

print (geeks)

Exit:

 True