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Python | Maximum absolute difference of the list

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Method # 1: Using max () + abs () + zip () + list comprehension
This particular problem can also be solved with a combination the above 4 operations. Here the zip function does a double task: to concatenate the list as well as concatenate the same indices for the difference to compute the abs function and then find the max using the max function , all limited to list comprehension.

# Python3 code for demonstration
# Maximum absolute difference of the list
# using max () + abs () + zip () + comprehension list

 
# init list

test_list = [[ 3 , 4 , 5 ], [ 4 , 6 , 8 ], [ 1 , 9 , 2 ], [ 3 , 7 , 10 ]]

 
# print original list

print ( "The original list:" + str (test_list))

 
# using max () + abs () + zip () + comprehension list
# Maximum absolute list difference

res = [ max ( abs (i - j) for i, j in zip ( * ele))

for ele in zip (test_list, test_list [ 1 :])]

 
# print result

print ( "The maximum difference sublist:" + str (res))

Output:

 The original list: [[3, 4, 5], [4, 6, 8], [1, 9, 2], [3, 7, 10] ]] The maximum difference sublist: [3, 6, 8] 

Method # 2: Using max () + map () + abs + zip ()
This task can also be achieved with a combination of the above functions, in addition to the map function which performs the task of binding the abs operation to the entire list.

# Python3 demo code
# Maximum absolute list difference
# using max () + map () + abs + zip ()

  
# init list

test_list = [[ 3 , 4 , 5 ], [ 4 , 6 , 8 ], [ 1 , 9 , 2 ], [ 3 , 7 , 10 ]]

 
# print original list

print ( "The original list:" + str (test_list))

 
# using max () + map () + abs + zip ()
# Maximum absolute list difference

res = [ max ( map ( abs , (i - j for i, j in zip (x, y))))

for x, y in zip (test_list, test_list [ 1 :])]

 
# print result

print ( "The maximum difference sublist:" + str (res))

Output:

 The original list: [[3, 4, 5], [4, 6, 8], [1, 9, 2], [3, 7, 10] ]] The maximum difference sublist: [3, 6, 8] 

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