Method # 1: Using List Comprehension
Using List Comprehension — it is a naive and brute force method to accomplish this particular task. In this method, we are trying to get the corresponding string using the "in" operator and store it in a new list.
| # Python3 code to demonstrate how it works
# Get matching substrings in a string
# Using comprehension list
# initialization string test_str = "GfG is good website"
# initializing potential substrings test_list = [ "GfG" , " site " , "CS" , "Geeks" , "Tutorial" ]
# print original line print ( "The original string is:" + test_str)
# print a list of potential lines print ( "The original list is: " + str (test_list))
# using comprehension list
# Get matching substrings in a string res = [sub for sub in test_list if sub in test_str]
# print result print ( "The list of found substrings: " + str (res)) |
Output:
The original string is: GfG is good website The original list is: [’GfG’,’ site’, ’CS’,’ Geeks’, ’Tutorial’] The list of found substrings: [’ GfG’, ’site’]
Method # 2: Using filter () + lambda
This task can also be performed using a filter function, which performs the task of filtering the resulting rows that are checked for existence using a lambda function.
| # Python3 code to demonstrate how it works
# Get matching substrings in a string
# Using lambda and filter ()
# initialization string test_str = "GfG is good website"
# initializing potential substrings test_ list = [ "GfG" , "site" , "CS" , "Geeks" , "Tutorial" ]
# print the original string print ( " The original string is: " + test_str)
# print a list of potential lines print ( "The original list is:" + str (test_list))
# using lambda and filter ()
# Get matching substrings in a string res = list ( filter ( lambda x: x in test_str, test_list))
# print result print ( "The list of found substrings:" + str (res)) |
Exit:
The original s tring is: GfG is good website The original list is: [’GfG’,’ site’, ’CS’,’ Geeks’, ’Tutorial’] The list of found substrings: [’ GfG’, ’site’]
