Method # 1: Using map () + count ()
The map function can be used to accumulate the indices of all tuples in a list, and the task of counting the frequency can be done using the Python library`s generic count function.

# Python3 demo code # search for frequency in a list of tuples # using map () + count ()    # initializing the list of tuples test_list = [( ` Geeks` , 1 ), ( `for` , 2 ), ( `Geeks` , 3 )]    # print original list print ( "The original list is:" + str (test_list))   # using the map () + count () # search for frequency in the list of tuples res = list ( map ( lambda i: i [ 0 < code class = "plain">], test_list)). count ( `Geeks` )   # print result print ( "The frequency of element is:" + str (res))

Exit:

 The original list is: [(`Geeks`, 1), (` for`, 2), (`Geeks` , 3)] The frequency of element is: 2 

Method # 2: Using Counter () + list comprehension
List comprehension function performs the task of getting the first element of tuples, and the counting part is processed by the Counter function of the collection library.

# Python3 code for demonstration # search for frequency in a list of tuples # using Counter () + list comprehension from collections import Counter   # initialize the list of tuples test_list = [( `Geeks` , 1 ), ( `for` , 2 ), ( ` Geeks` , 3 )]   # print origin list print ( "The original list is: " + str (test_list))   # using Counter () + list comprehension # find frequency in list of tuples res = Counter (i [ 0 ] for i in test_list)   # print result print ( "The frequency of element is:" +  str (res [ `Geeks` ]))

Output:

 The original list is: [(`Geeks`, 1), (` for`, 2), (`Geeks`, 3)] The frequency of element is: 2