Method # 1: Using map () + count ()
The map function can be used to accumulate the indices of all tuples in a list, and the task of counting the frequency can be done using the Python library’s generic count function.
| # Python3 demo code
# search for frequency in a list of tuples
# using map () + count ()
# initializing the list of tuples test_list = [( ’ Geeks’ , 1 ), ( ’for’ , 2 ), ( ’Geeks’ , 3 )]
# print original list print ( "The original list is:" + str (test_list))
# using the map () + count ()
# search for frequency in the list of tuples res = list ( map ( lambda i: i [ 0 < code class = "plain">], test_list)). count ( ’Geeks’ )
# print result print ( "The frequency of element is:" + str (res)) |
Exit:
The original list is: [(’Geeks’, 1), (’ for’, 2), (’Geeks’ , 3)] The frequency of element is: 2
Method # 2: Using Counter () + list comprehension
List comprehension function performs the task of getting the first element of tuples, and the counting part is processed by the Counter function of the collection library.
| # Python3 code for demonstration
# search for frequency in a list of tuples
# using Counter () + list comprehension from collections import Counter
# initialize the list of tuples test_list = [( ’Geeks’ , 1 ), ( ’for’ , 2 ), ( ’ Geeks’ , 3 )]
# print origin list print ( "The original list is: " + str (test_list))
# using Counter () + list comprehension
# find frequency in list of tuples res = Counter (i [ 0 ] for i in test_list)
# print result print ( "The frequency of element is:" + str (res [ ’Geeks’ ])) |
Output:
The original list is: [(’Geeks’, 1), (’ for’, 2), (’Geeks’, 3)] The frequency of element is: 2
