Python | Find who tweeted the most



Notes:
If multiple users have the same number of tweets, print all users in alphabetical order of usernames.

Input format:

 Read the input from the console. The first line of input should be the number of test cases Remaining lines of input should contain each test case input. 

For each entry test case:

 First-line should contain the number of tweets. Followed by N lines, each containing the user name and tweet id separated by a space. 

Output format:

 Find the user with max number of tweets. Print user name and the total number of tweets. 

Examples :

  Input:  1 4 sachin tweet_id_1 sehwag tweet_id_2 sachin tweet_id_3 sachin tweet_id_4  Output:  sachin 3  Input:  1 6 sachin tweet_id_1 sehwag tweet_id_2 sachin tweet_id_3 sehwag tweet_id_4 kohli tweet_id_5 kohli tweet_id_6  Output:  kohli 2 sachin 2  bohli 2 sachin 2  > Code: Python Implementation for finding who tweeted the most  

# Write Python3 code here
# collection module using dic count for value and keys

from collections import Counter

 

tweet_names = [ "sachin tweet_id_1"

  " sehwag tweet_id_2 " ,

  " sachin tweet_id_3 " ,

  " sachin tweet_id_4 "

  

uniq_names = [pref_names.split () [ 0 ] for

pref_names in tweet_names]

 

times = Counter (uniq_names)

repeat = times.values ​​()

 

for element in set (repeat):

dupl = ([(key, value) for

key, value in sorted (times.items ()) if

value = = element])

  

  if len (dupl) & gt;  1 :

for (key, value) in dupl:

print (key , ``, value)

max_value = max (times.values ​​())

  temp_max_result = [(key, value) for  

key, value in sorted (times.items ()) if

  value = = max_value]

 

if temp_max_result! = dupl:

  for ( key, value) in temp_max_result:

  print (key, ``, value)

  

Output:

 sachin 3