Method # 1: Using List Comprehension + len()
A combination of the above functions can be used to accomplish this task. In this case, we iterate over all rows and return only K-sized rows checked with len ().
| # Python3 code to demonstrate how it works
# Extract K-sized lines
# using a list comprehension + len ()
# initialize list test_list = [ ’gfg’ , ’is’ , ’ best’ , ’for’ , ’geeks’ ]
# print original list print ( "The original list:" + str (test_list))
# initialize K K = 3
# Extract K-sized lines
# using list comprehension + len () res = [ele for ele in test_list if len (ele ) = = K]
# print result print ( "The K sized strings are:" + str (res)) |
Output:
The original list: [’gfg’,’ is’, ’best’,’ for’, ’geeks’] The K sized strings are: [’gfg’,’ for’]
Method # 2: Using filter () + lambda
A combination of the above functions can be used to accomplish this task. In this we extract the elements using filter () and the logic is compiled into a lambda function.
| # Python3 code to demonstrate how it works
# Extract K-sized lines
# using filter () + lambd
# initialize the list test_list = [ ’gfg’ , ’is’ , ’ best’ , ’for’ , ’ geeks’ ]
# p Printing original list print ( "The original list: " + str (test_list))
# initialize K K = 3
# Extract K-sized lines
# using () + lambda filter res = list ( filter ( lambda ele: len (ele) = = K, test_list))
# print result print ( "The K sized strings are:" + str (res)) |
Output:
The original list: [’gfg’,’ is’, ’best’,’ for’, ’geeks’] The K sized strings are: [’ gfg’, ’for’]
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