zip () + product ()
These functions can solve this problem and require two steps to complete. In step 1 we find all combinations of elements using
product () and as part of step 2 we do a possible conjugation with the result of step 1 using
zip () and display the desired result.
The original list 1 is: [3, 4, 5]
The original list 2 is: ['x', 'y ']
Mapped Combination result: [[(3,' x '), (4,' x '), (5,' x ')], [(3,' x '), (4,' x '), (5,' y ')], [(3,' x '), (4,' y '), (5,' x ')], [(3,' x '), (4 , 'y'), (5, 'y')], [(3, 'y'), (4, 'x'), (5, 'x')], [(3, 'y'), (4, 'x'), (5, 'y')], [(3, 'y'), (4, 'y'), (5, 'x')], [(3, 'y' ), (4, 'y'), (5, 'y')]]
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