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Counter Python | Find duplicate rows in a binary matrix

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Examples:

 Input: [[1, 1, 0, 1, 0, 1], [0, 0, 1, 0, 0, 1], [1, 0, 1, 1, 0, 0], [1, 1, 0, 1, 0, 1], [0, 0, 1, 0, 0, 1], [0, 0, 1, 0, 0, 1]] Output : (1, 1, 0, 1, 0, 1) (0, 0, 1, 0, 0, 1) 

We have a solution to this problem, please refer to the section Counter () method. The approach is very simple,

  1. Create a dictionary using the counter method, in which the strings will have a key value, and its frequency is — value.
  2. Now go through the dictionary completely and print all lines with a frequency greater than 1.

# Function for finding duplicate rows in a binary matrix

from collections import Counter

 

def duplicate ( input ):

 

# since lists are not available for the counter method

# because the lists are mutable, so we will cite first

# each line (list) in a tuple

input = map ( tuple , input )

 

# now creating a dictionary

freqDict = Counter ( input )

  

# print all lines with a frequency greater than 1

for (row, freq) < / code> in freqDict.items ():

if freq" 1 :

  print (row )

 
# Driver program

if __ name__ = = "__ main__" :

  input = [[ 1 , 1 , 0 , 1 , 0 , 1 ],

[ 0 , 0 , 1 , 0 , 0 , 1 ],

[ 1 , 0 , 1 , 1 , 0 , 0 ],

 

[ 1 , 1 , 0 , 1 , 0 , 1 ],

[ 0 , 0 , 1 , 0 , 0 , 1 ],

[ 0 , 0 , 1 , 0 , 0 , 1 ]]

duplicate ( input )

Output:

 (1, 1, 0, 1, 0, 1) (0, 0, 1, 0, 0, 1) 

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