 # Python | Counting keys with a specific value in a dictionary

Method # 1: Using a loop
This problem can be solved using the naive looping method. In this, we simply iterate over each key in the dictionary, and when a match is found, the counter increments.

 ` # Python3 code to demonstrate how it works ` ` # Number of keys with a specific value in the dictionary ` ` # Using a loop `   ` # Initialize dictionary ` ` test_dict ` ` = ` ` {` ` `gfg` ` `: ` ` 1 ` `, ` ` `is` ` `: ` ` 2 ` `, ` ` `best` ` `: ` ` 3 ` `, ` < code class = "string"> `for` `: ` ` 2 ` `, ` ` `CS` ` `: ` ` 2 ` `} ` ` `  ` # print original dictionary ` ` print ` ` (` ` "The original dictionary:" ` ` + ` ` str ` ` (test_dict)) `   ` # Initialize value ` ` K ` ` = ` ` 2 `   ` # Using a loop ` ` # Selected key values ​​in the dictionary ` ` res ` ` = ` ` 0 ` ` for ` ` key ` ` in ` ` test_dict: ` ` if ` ` test_dict [key] ` ` = ` ` = ` ` K: ` ` res ` ` = ` ` res ` ` + 1 ````   # print result print ( "Frequency of K is: " + str (res)) ```

Output:

< blockquote>

The original dictionary: {`gfg`: 1, `CS`: 2, `best`: 3, `for`: 2, `is`: 2}
Frequency of K is: 3

Method # 2: Using ` sum () + values ​​() `
This can also be solved using the combination ` sum () and value () `. In this case, the sum is used to perform the summation of the filtered values, and the dictionary values ​​are retrieved using `values()`

` `

``` # Python3 code to demonstrate how it works # Number of keys with a specific value in the dictionary # Using sum () + values ​​()   # Initialize dictionary test_dict = { `gfg` : 1 , `is` : 2 , `best` : 3 , `for` : 2 , `CS` : 2 }    # print the original dictionary print ( "The original dictionary:" +   str (test_dict))   # Initialize value K = 2   # Using sum () + values ​​() # Choice actual key values ​​in the dictionary res = sum (x = = K for x in test_dict.values ​​())   # print result print ( "Frequency of K is : " + str (res)) ```

` ` Output:

The original dictionary: {` gfg `: 1,` CS `: 2,` best `: 3,` for `: 2,` is`: 2}
Frequency of K is: 3