Method # 1: Using split ()
+ understanding vocabulary
A combination of the above methods can be used to accomplish this particular task. These are 2 processes. In the first step, the string is converted to a list using split, and then converted back to a dictionary using dictionary comprehension.
# Python3 demo code # Converting string content to dictionary # Using dictionary comprehension + split () # initialization string test_str = "Gfg = 1, Good = 2, CS = 3, Portal = 4" # print original line print ( " The original string is: " + test_str) # Using dictionary comprehension + split () # Convert string content to dictionary res = {key: int (val) for key, val in (item.split ( ’=’ ) for item in test_str.split ( ’, ’ ))} # print result print ( "The newly created dictionary:" + str (res)) |
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Output:
The original string is: Gfg = 1, Good = 2, CS = 3, Portal = 4 The newly created dictionary: {’CS’: 3, ’Gfg’: 1, ’Portal’: 4, ’Good’: 2}
Method # 2: Using eval ()
This particular problem can be solved with the built-in eval
function which internally evaluates the string and converts the string to a dictionary depending on the condition.
# Python3 code to demonstrate how it works # Convert string content to dictionary # Using eval () # initialization string test_str = "Gfg = 1, Good = 2, CS = 3, Portal = 4 " # print original line print ( "The original string is:" + test_str) # Using eval () # Convert string content to dictionary res = eval ( ’dict (% s)’ % test_str) p> # print result print ( " The newly created dictionary: " + str (res)) |
Python | Converting string content to dictionary __dict__: Questions
Python | Converting string content to dictionary Python functions: Questions