Method # 1: Using split () + understanding vocabulary
A combination of the above methods can be used to accomplish this particular task. These are 2 processes. In the first step, the string is converted to a list using split, and then converted back to a dictionary using dictionary comprehension.
| # Python3 demo code
# Converting string content to dictionary
# Using dictionary comprehension + split ()
# initialization string test_str = "Gfg = 1, Good = 2, CS = 3, Portal = 4"
# print original line print ( " The original string is: " + test_str)
# Using dictionary comprehension + split ()
# Convert string content to dictionary res = {key: int (val) for key, val in (item.split ( ’=’ ) for item in test_str.split ( ’, ’ ))}
# print result print ( "The newly created dictionary:" + str (res)) |
Output:
The original string is: Gfg = 1, Good = 2, CS = 3, Portal = 4 The newly created dictionary: {’CS’: 3, ’Gfg’: 1, ’Portal’: 4, ’Good’: 2} Method # 2: Using eval ()
This particular problem can be solved with the built-in eval function which internally evaluates the string and converts the string to a dictionary depending on the condition.
| # Python3 code to demonstrate how it works
# Convert string content to dictionary
# Using eval ()
# initialization string test_str = "Gfg = 1, Good = 2, CS = 3, Portal = 4 "
# print original line print ( "The original string is:" + test_str)
# Using eval ()
# Convert string content to dictionary res = eval ( ’dict (% s)’ % test_str)
# print result print ( " The newly created dictionary: " + str (res)) |
