Method # 1: Using eval () + list comprehension
This problem can be easily solved as one liner using the built-in eval ( ) which does this task of converting a string to a tuple and comprehending a list.

# Python3 code to demonstrate how it works # Convert string tuples to list of tuples # use comprehension list + eval ()   # Initializing list test_list = [ "(` gfg`, 1) " , "(` is`, 2) " , "(` best`, 3) " ]    # print the original list print ( " The original list is: " + str (test_list))   # Convert string tuples to a list of tuples # use comprehension list + eval () res = [ eval (ele) for ele in test_list]   # print result print ( "The list tuple after conversion:" + str (res))

Output:

 The original list is: ["(` gfg`, 1) "," (`is `, 2)", "(` best`, 3) "] The list tuple after conversion: [(` gfg`, 1), (`is`, 2), (` best`, 3)]  
 
  Method # 2: Using  eval () + map ()   
 This task can also be accomplished using a combination of the above functions. The task performed by the above list can be accomplished with  map ()  in this method. 
 
 
 
 
   
 
 
 
 
  # Python3 code to demonstrate how it works  
  # Convert string tuples to list of tuples  
  # using map () + eval ()  
 
  
  # Initializing list  
 
  test_list   =   [  "(` gfg` , 1) " ,  " (`is`, 2)"   ,   "(` best`, 3) " ] 
 
  
  # print original list  
 
  pr int   (  "The original list is:"   +   str   (test_list)) 
 
  
  # Convert string tuples to list of tuples  
  # using map () + eval ()   
  res   =   list   (  map   (  eval  , test_list)) 
 
   
  # print result  
 
  print   (  "The list tuple after conversion:"   +   str   (res))  
 
 
 
 
 
   Output:  
 
 The original list is: ["(` gfg`, 1) "," (`is`, 2)", "(` best`, 3) "] The list tuple after conversion: [(` gfg`, 1), (`is` , 2), (`best`, 3)]