Method # 1: Using eval () + list comprehension
This problem can be easily solved as one liner using the built-in eval ( ) which does this task of converting a string to a tuple and comprehending a list.
| # Python3 code to demonstrate how it works
# Convert string tuples to list of tuples
# use comprehension list + eval ()
# Initializing list test_list = [ "(’ gfg’, 1) " , "(’ is’, 2) " , "(’ best’, 3) " ]
# print the original list print ( " The original list is: " + str (test_list))
# Convert string tuples to a list of tuples
# use comprehension list + eval () res = [ eval (ele) for ele in test_list]
# print result print ( "The list tuple after conversion:" + str (res)) |
Output:
The original list is: ["(’ gfg’, 1) "," (’is ’, 2)", "(’ best’, 3) "] The list tuple after conversion: [(’ gfg’, 1), (’is’, 2), (’ best’, 3)]
Method # 2: Using eval () + map ()
This task can also be accomplished using a combination of the above functions. The task performed by the above list can be accomplished with map () in this method.
| # Python3 code to demonstrate how it works
# Convert string tuples to list of tuples
# using map () + eval ()
# Initializing list test_list = [ "(’ gfg’ , 1) " , " (’is’, 2)" , "(’ best’, 3) " ]
# print original list pr int ( "The original list is:" + str (test_list))
# Convert string tuples to list of tuples
# using map () + eval () res = list ( map ( eval , test_list))
# print result print ( "The list tuple after conversion:" + str (res)) |
Output:
The original list is: ["(’ gfg’, 1) "," (’is’, 2)", "(’ best’, 3) "] The list tuple after conversion: [(’ gfg’, 1), (’is’ , 2), (’best’, 3)]
