Python | Build a list of alignment strings for a range N

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Method # 1: Using List Comprehension + zfill()
A combination of the above functions can be used to accomplish this task. In this we perform the task of adding numbers using a list comprehension, and zfill () takes care of the length required for each line.

# Python3 code to demonstrate how it works
# Construct N Range Equilength String list
# using a list comprehension + zfill ()


# initialize N

N = 6


# print N

print ( " Number of elements required: " + str (N))


# initialize K

K = 3


# Construct N Range Equilength String list
# using a list comprehension + zfill ()

res = [ str (ele) .zfill (K) for ele in range (N)]


# print result

print ( "K Length range strings list:" + str (res))

Output:

 Number of elements required: 6 K Length range strings list: [’000’,’ 001’, ’002’,’ 003’, ’004’, ’005’] 

Method # 2: Using map () + string formatting
This task can also be done using the above functions. In this, we extend the length logic using string formatting. And it is used to plot the N range.

# Python3 code to demonstrate how it works
# Construct N Range Equilength String list
# using map () + string formatting


# initialize N

N = 6


# print N

print ( "Number of elements required: " + str (N))


# initialize K

K = 3


# Construct N Range Equilength String list
# using map () + string formatting

temp = ’{: 0’ + str (K) + ’}’

res = list ( map (temp. format , range (N)))


# print result

print ( "K Length range strings list:" + str (res))

Output:

 Number of elements required: 6 K Length range strings list: [’ 000’, ’001’,’ 002’, ’003’,’ 004’, ’005’] 

Python | Build a list of alignment strings for a range N log: Questions

log

Python"s equivalent of && (logical-and) in an if-statement

5 answers

delete By delete

Here"s my code:

def front_back(a, b):
  # +++your code here+++
  if len(a) % 2 == 0 && len(b) % 2 == 0:
    return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] 
  else:
    #todo! Not yet done. :P
  return

I"m getting an error in the IF conditional.
What am I doing wrong?

934

Answer #1

You would want and instead of &&.

934

Answer #2

Python uses and and or conditionals.

i.e.

if foo == "abc" and bar == "bac" or zoo == "123":
  # do something

log

How do you get the logical xor of two variables in Python?

5 answers

Zach Hirsch By Zach Hirsch

How do you get the logical xor of two variables in Python?

For example, I have two variables that I expect to be strings. I want to test that only one of them contains a True value (is not None or the empty string):

str1 = raw_input("Enter string one:")
str2 = raw_input("Enter string two:")
if logical_xor(str1, str2):
    print "ok"
else:
    print "bad"

The ^ operator seems to be bitwise, and not defined on all objects:

>>> 1 ^ 1
0
>>> 2 ^ 1
3
>>> "abc" ^ ""
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for ^: "str" and "str"
794

Answer #1

If you"re already normalizing the inputs to booleans, then != is xor.

bool(a) != bool(b)

Python | Build a list of alignment strings for a range N Python functions: Questions

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