Method # 1: Using join () + zip ()
+ expression generator
A combination of the above functions can be used to solve this problem. In this, we perform the task of concatenating sequential characters using zip (), and a generator expression is used to provide the paging logic.
# Python3 code to demonstrate how it works # Sequentially swapping elements in a line # using join () + zip () + expression generator # initialization string test_str = "gfgisbesty" # print original line print ( "The original string is:" + test_str) # Sequential exchange of elements in a line # using join () + zip () + expression generator res = ’’ .join ([char [ 1 ] + char [ 0 ] for char in zip (test_str [:: 2 ], test_str [ 1 :: 2 ])]) # print result print ( "String after Consecutive Swapping:" + str (res)) |
table> Output:
The original string is: gfgisbesty String after Consecutive Swapping: fgigbsseyt
Method # 2: Using a Regular Expression
This task can also be accomplished by using a regular expression using a correctly substituted regular expression.
# Python3 code to demonstrate how it works # Sequential exchange of elements in a string # using a regular expression import re # initialization string test_str = "gfgisbesty" # print original line print ( "The original string is:" + test_str) # Sequential exchange of elements in a line # using regular expression res = re.sub (r ’(.) (.)’ , r ’21’ , test_str) # print result print ( "String after Consecutive Swapping:" + str (res)) |
Output:
The original string is: gfgisbesty String after Consecutive Swapping: fgigbsseyt
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