# Python | Check if the list contains sequential numbers

Examples :

`  Input:  [2, 3, 1, 4, 5]  Output:  True  Input:  [1, 2, 3, 5, 6]  Output:  False `

Let’s discuss several ways we can accomplish this task.

Approach # 1: with `sorted()`

This approach uses ` sorted () ` Python. We compare the sorted list with the list of the minimum and maximum integer range of the list and return it.

 ` # Python3 List generator ` ` # with integers in the given range `   ` def ` ` checkConsecutive (l): ` ` ` ` return ` ` sorted ` ` (l) ` ` = ` ` = ` ` list ` ` (` ` range ` ` (` ` min ` ` (l), ` ` max ` ` (l) ` ` + ` ` 1 ` `)) ` ` `  ` Driver code ` ` lst ` ` = ` ` [` ` 2 ` `, ` ` 3 ` `, ` ` 1 ` `, ` ` 4 ` `, ` ` 5 ` `] ` ` print ` ` (checkConsecutive (lst)) `

Exit :

` True `

Approach # 2 Usage `numpy.diff()`

The Numpy module provides a ` diff () ` function that computes the nth discrete difference along a given axis. We find the iterative difference of the sorted list and check if it is equal to 1.

 ` # Python3 List generator ` ` # with integers in the given range ` ` import ` ` numpy as np `   ` def ` ` checkConsecutive ( l): ` ` n ` ` = ` ` len ` ` (l) ` ` - ` ` 1 ` ` ` ` return ` ` (` ` sum ` ` (np.diff (` ` sorted ` ` (l)) ` ` = ` ` = ` ` 1 ` `)" ` ` = ` ` n) `   ` Driver code ` ` lst ` ` = ` ` [` ` 2 ` `, ` ` 3 ` `, ` ` 1 ` `, ` ` 4 ` `, ` ` 5 ` `] ` ` print ` ` (checkConsecutive (lst)) `

Exit :

` True `

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