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Python | Check if the list contains all unique items

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Method # 1: The Naive Method
Solutions usually start with the simplest method that can be applied to a specific task. Here you can use a nested loop to check if a similar element exists after this element in the remaining list.

# Python3 demo code
# to check all items in the list are unique
# using a naive method

 
# initializing list

test_list = [ 1 , 3 , 4 , 6 , 7 ]

   # print original list

print ( "The original list is:" + str (test_list))

 

flag = 0

 
# using the naive method
# check all unique list items

for i in range ( len (test_list)):

for i1 i n range ( len (test_list)):

  if i! = i1:

  if test_list [i] = = test_list [i1]:

flag = 1

 

  
# print result

if ( not flag ):

  print ( "List contains all unique elements" )

else

print ( "List contains does not contain all unique elements " )

Output:

 The original list is: [1, 3, 4, 6, 7] List contains all unique elements 

Method # 2: Using len () + set ()
This is the most elegant way to solve this problem with one line. This solution converts the list to install and then tests with the original list if it contains a similar number. elements.

# Python3 demo code
# to check all items in the list are unique
# using set () + len ()

 
# initializing list

test_list = [ 1 , 3 , 4 , 6 , 7 ]

 
# print original list

print ( "The original list is:" + str (test_list))

 

flag = 0

  
# using set () + len ()
# check all unique list items

flag = len ( set (test_list)) = = len (test_list)

 

 
# print result

< code class = "keyword"> if (flag):

print ( "List contains all unique elements" )

else

print ( "List contains does not contain all unique elements " )

Output:

 The original list is: [1, 3, 4, 6, 7] List contains all unique elements 

Method # 3: Using Counter.itervalues()
This is one of various methods that uses the frequency obtained for all elements using a counter and checks , whether any of the frequencies exceeds 1.

Output:

 The original list is: [1, 3, 4, 6, 7] List contains all unique elements 

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# Python code for demo
# to check all items in the list are unique
# using Counter.itervalues ​​()

from collections import Counter

 
# initializing list

test_list = [ 1 , 3 , 4 , 6 , 7 ]

  
# print the original list

print ( " The original list is: " + str (test_list))

 

flag = 0

  
# using Counter.itervalues ​​()
# check all unique list items

counter = Counter (test_list)

for values ​​ in counter.itervalues ​​():

  if values ​​& gt;  1 :

flag = 1

 

 
# print result

if ( not flag):

  print ( "List contains all unique elements" )

else

  print ( "List contains does not contains all unique elements" )