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# Python | Check if the list exists in the given list of lists

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For a given list of lists, the task is to check if the list exists in the given list of lists.

`  Input:  lst = [[1, 1, 1, 2 ], [2, 3, 4], [1, 2, 3], [4, 5, 6]] list_search = [4, 5, 6]  Output:  True  Input:  lst = [[5, 6, 7], [12, 54, 9], [1, 2, 3]] list_search = [4, 12, 54]  Output:  False `

Let’s discuss some ways to accomplish this task.

Method # 1: Using a counter
Most concise and readable a way to find out if a list exists in a list of lists, — use Counter.

 ` # Python code to find the list ` ` # exists in the list ` ` import ` ` collections ` ` `  ` # Initialize the input list ` ` Input ` ` = ` ` [[` ` 1 ` `, ` ` 1 ` `, ` ` 1 ` `, ` ` 2 ` `], [` ` 2 ` `, ` ` 3 ` `, ` ` 4 ` `], [` ` 1 ` `, 2 , 3 ] , [ 4 , 5 , 6 ]] ``    # Search list list_search = [ 2 , 3 , 4 ]   # Initialization flag flag = 0      # Using the counter for elem in Input : if collections.Counter (elem) = = collections. Counter (list_search): flag = 1   # Check if the list exists or not. if flag = = 0 : print ( " False " ) else : print ( " True " ) `

Output:

` True `

Method # 2: Using in

` `

` Exit: True Method # 3: Using any # Does Python code find the list # exists in the list.   # Initialize the input list Input = [[ 1 , 1 , 1 , 2 ], [ 2 , 3 , 4 ], [ 1 , 2 , 3 ], [ 4 , 5 , 6 ]]   # Search list list_search = [ 1 , 1 , 1 , 2 ]   # Use in to find whether # the list exists or not if list_search in Input : print ( "True" ) else :   print ( "False" ) # Python code to find the list # exists in the list.   # Initialize the input list Input = [[ 1 , 1 , 1 , 2 ], [ 2 , 3 , 4 ], [ 1 , 2 , 3 ], [ 4 , 5 , 6 ]]   # Search list list_search = [ 4 , 5 , 6 ]   # Using any to find # whether the list exists or not if any ( list = = list_search for list in Input ):   print ( " True " ) else : print ( " False " )    `

` ` Exit :

` True `

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