Python — widely used universal high-level programming language. It provides many functions and one of them — checking if the directory is empty or not. This can be achieved with the OS module . The os.listdir () method os.listdir () os module method is used to get list all files and directories in the specified directory.
Syntax: os.listdir (path)
Parameters:
path (optional): path of the directory
Return Type: This method returns the list of all files and directories in the specified path ... The return type of this method is list.
Example # 1: If the list returned by os.listdir () is empty, then the directory is empty, otherwise not. Below is the implementation.
| # Python program for checking
# empty directory or not import os
# path to directory path = "D: / Pycharm projects / Python.Engineering / Nikhil"
# Get directory listing dir = os.listdir (path)
# Check if the list is empty or not if len ( dir ) = = 0 : print ( "Empty directory" ) else : print ( " Not empty directory " ) |
Exit:
Empty directory
Example # 2. Suppose the path given in the above code is the path to a text file or the wrong way, then in this case Sometimes the above code will raise OSError . To overcome this error, we can use os.path.exists () . Below is the implementation.
| # Python checker
# is the directory empty or not import os
# Function to check if the path is specified
# correct directory specified def isEmpty (path): if os.path.exists (path) and not os.path.isfile (path): # Check if the directory is empty or not if not os.listdir (path): print ( "Empty directory" ) else : print ( "Not empty directory" ) else : print ( < code class = "string"> "The path is either for a file or not valid" )
# file path path = "D: / Pycharm projects / Python.Engineering / Nikhil / gfg. txt " isEmpty (path) print ()
# valid path path = "D: / Pycharm projects / Python.Engineering / Nikhil / " isEmpty (path) |
Exit :
The path is either for a file or not valid Not empty directory
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