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Python | Add occurrences of each number as sublists

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Examples :

`  Input:  l1 = [3, 5, 7, 2, 3, 5, 9.1]  Output:  [[3, 2], [5, 2], [7, 1], [2, 1], [9.1, 1]]  Input:  l1 = [1, 1 , 2, 2, 3, 1]  Output:  [[1, 3], [2, 2], [3, 1]] `

Note. Format for displaying the list 2d: [[& # 39; item1 & # 39 ;, & # 39; count1 & # 39;], [& # 39; item2 & # 39 ;, & # 39; count2 & # 39;], ... , [& # 39; itemN & # 39 ;, & # 39; countN & # 39;]].

Code # 1: Using the count () method

 ` # Python program to add an entry ` ` # of each number as sublists ` ` def ` ` count_occur (list1, ` ` * ` ` * ` ` kwargs): ` ` `  ` ` ` # iterate over the list item ` ` for ` ` i ` ` in ` ` list1: ` ` row ` ` = ` ` [] ` ` ct ` ` = ` ` 0 `   ` The # count function will count occurrences ` ` ct ` ` = ` ` list1.count (i) ` ` row.append (i) ` ` row .append (ct) ` ` # add 1d list items to 2d list ` ` list2.append (row) `   ` ` ` # code below to eliminate ` ` # duplicate list items ` ` ` ` for ` ` j ` ` in ` ` list2: ` ` if ` ` j ` ` not ` ` in ` ` unq_l2: ` ` unq_l2.append (j) ` `  `` return unq_l2   Driver code l1 = [ 3 , 5 , 7 , 2 , 3 , 5 , 9.1 ] list2 = [] unq_l2 = [] print (count_occur (l1)) `

Exit:

` [[3, 2 ], [5, 2], [7, 1], [2, 1], [9.1, 1]] `

Code # 2: Using the loop method

 ` def ` ` count_occur (list1): `   ` ` ` for ` ` i ` ` in ` ` range ` ` (` ` 0 ` `, ` ` len ` ` (l1)): ` ` a ` ` = ` ` 0 ` ` ` ` row ` ` = ` ` [] ` ` if ` ` i ` ` not ` ` in ` ` l: ` ` for ` ` j ` ` in ` ` range ` ` (` ` 0 ` `, ` ` len ` ` (l1)): ` ` ` ` # match items from both lists ` ` if ` ` l1 [i] ` ` = ` ` = ` ` l1 [j]: ` ` ` ` # when the match counter is increased by 1 ` ` ` ` a ` ` = ` ` a ` ` + ` ` 1 ` ` row.append (l1 [i]) ` ` row.append (a) ` ` # append function will add ` ` ` ` # 1d list of items in 2d list ` ` ` ` l.append (row) `   ` ` ` # below code to fix ` ` # duplicate list items ` ` for ` ` j ` ` in ` ` l: ` ` ` ` if ` ` j ` ` not ` ` in ` ` unq_l: ` ` unq_l.append (j ) `   ` return ` ` unq_l ` ` `  ` # Driver code ` ` l1 ` ` = ` ` [` ` 3 ` `, ` ` 5 ` `, ` ` 7 ` `, ` ` 2 ` `, ` ` 3 ` `, 5 , 9.1 ] `` l = [] unq_l = []   print (count_occur (l1 )) `

Exit:

` [ [3, 2], [5, 2], [7, 1], [2, 1], [9.1, 1]] `

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