Syntax:bool Imagick::previousImage (void)
Parameters:This function takes no parameters.
Returned value:This function returns TRUE on success.
Exceptions :this function throws an ImagickException on error.The following programs illustrate the Imagick::previousImage() function in PHP:
Program 1:
// Create a new imagick object $imagick = new Imagick ( ’ https://media.engineerforengineer.org/wp-content/uploads/engineerforengineer-13.png ’ ) ;
// Add an image to the imagick object. $imagick -> addImage ( new Imagick ( ’ https://media.engineerforengineer.org/wp-content/uploads/20190918234528/colorize1.png ’ ));
// Get index $index1 = $imagick -> getIteratorIndex(); echo ’Before:’ . $index1 . ’
’ ;
// Move cursor to first image $imagick -> previousImage(); $imagick -> previousImage();
// Get index $index2 = $imagick -> getIteratorIndex(); echo ’After:’ . $index2 . ’
’ ; ?> Output:Before: 1 After: 0
Program 2:
// Create a new imagick object $imagick = new Imagick ( ’ https://media.engineerforengineer.org/wp-content/uploads/20190918234528/colorize1.png ’ ) ;
// Add an image to the imagick object. $imagick -> addImage ( new Imagick ( ’ https://media.engineerforengineer.org/wp-content/uploads/engineerforengineer-13.png ’ ));
// Move cursor to first image $imagick -> previousImage(); $imagick -> previousImage();
// Show image header ( "Content-Type: image / png" ); echo $imagick -> getImageBlob(); ?> Output: Link: https://www.php.net/manual/en/imagick.previousimage.php
