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numpy.tile () in Python

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Parameters :

  array:  [array_like] Input array.  repetitions:  No. of repetitions of arr along each axis. 

Return:

 An array with repetitions of array - arr as per d, number of times we want to repeat arr 

Code 1:

# Python program illustrating
# numpy.tile ()

 

import numpy as geek

 
# Working on 1D

arr = geek.arange ( 5 )

print ( "arr:" , arr)

 

repetitions = 2

print ( "Repeating arr 2 times:" , geek.tile (arr , repetitions))

 

repetitions = 3

print ( " Repeating arr 3 times: " , geek.tile (arr, repetitions))

# [0 1 2 ..., 2 3 4] means [0 1 2 3 4 0 1 2 3 4 0 1 2 3 4]
# since this was long output, so it uses [...]

Output:

 arr: [0 1 2 3 4] Repeating arr 2 times: [0 1 2 3 4 0 1 2 3 4] Repeating arr 3 times: [0 1 2 ..., 2 3 4] 

Code 2:

# Python program illustrating
# numpy .tile ()

 

import numpy as geek

 

arr = geek.arange ( 3 )

print ( " arr: " , arr)

  

a = 2  

b = 2  

repetitio ns = (a, b)

print ( "Repeating arr:" , geek.tile (arr, repetitions))

print ( "arr Shape: " , geek.tile (arr, repetitions) .shape)

  

a = 3  

b = 2  

repetitions = (a, b)

print ( "Repeating arr:" , geek.tile (arr, repetitions))

print ( "arr Shape:" , geek.tile (arr, repetitions) .shape)

 

a = 2

b = 3  

repetitions = (a, b)

print ( "Repeating arr:" , geek.tile (arr, repetitions))

print ( "arr Shape:" , geek.tile (arr , repetitions) .shape)

Output:

 arr: [0 1 2] Repeating arr: [[0 1 2 0 1 2] [0 1 2 0 1 2]] arr Shape: (2, 6) Repeating ar r: [[0 1 2 0 1 2] [0 1 2 0 1 2] [0 1 2 0 1 2]] arr Shape: (3, 6) Repeating arr: [[0 1 2 ..., 0 1 2] [0 1 2 ..., 0 1 2]] arr Shape: (2, 9) 

Code 3: (repetitions == arr.ndim) == 0

# Python program illustrating
# numpy.tile ()

 

import numpy as geek

 

arr = geek.arange ( 4 ). reshape ( 2 , 2 )

print ( "arr:" , arr)

 

a = 2  

b = 1  

repetitions = (a, b)

print ( "Repeating arr:" , geek.tile (arr, repetitions))

print ( "arr Shape:" , geek.tile (arr, repetitions) .shape)

 

a = 3  

b = 2  

re petitions = (a, b)

print ( "Repeating arr:" , geek.tile (arr, repetitions))

print ( "arr Shape: " , geek.tile (arr, repetitions) .shape)

  

a = 2

b = 3  

repetitions = (a, b)

print ( "Repeating arr:" , geek.tile (arr, repetitions))

print < code class = "plain"> ( "arr Shape:" , geek.tile (arr, repetitions) .shape)

Output:

 arr: [[0 1] [2 3]] Repeating arr: [[0 1] [2 3] [0 1] [2 3]] arr Shape: (4, 2) Repeating arr: [[0 1 0 1] [2 3 2 3] [0 1 0 1] [2 3 2 3] [0 1 0 1] [2 3 2 3]] arr Shape: (6, 4) Repeating arr: [[0 1 0 1 0 1] [2 3 2 3 2 3] [0 1 0 1 0 1] [2 3 2 3 2 3]] arr Shape: (4, 6) 

Links:
numpy.tile.html> https://docs.scipy.org/doc/numpy/ reference / generated / numpy.tile.html

Notes:
These codes will not work for online IDs. Please run them on your systems to see how they work

This article is provided by Mohit Gupta_OMG

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