isdigit | NumPy | Python Methods and Functions | String Variables

numpy.core.defchararray.isdigit (arr) returns True for each item if all characters in the string are numbers and there is at least one character; otherwise returns false

Parameters:
arr: array_like of str or unicode.

Returns: [ndarray] Output array of bools.

Code # 1:

# Python program explaining # numpy.char.isdigit () method   import numpy as geek   # input array contains only numbers in_arr = geek.array ([ ` 1000` , `2000` ]) print ( "Input array:" , in_arr)    out_arr = geek.char.isdigit (in_arr) print ( "Output array:" , out_arr)

Output :

 Input array: [`1000`` 2000`] Output array: [ True True] 

Code # 2:

# Python program explaining # numpy.char.isdigit () method   import numpy as geek    # input array contains numbers along with spaces and alphabets in_arr = geek.array ([ ` 1000 2` , `a1000` , ` 1234 ab` ]) print ( " Input array: " , in_arr)    out_arr = geek.char.isdigit (in_arr) print ( " Output array: " , out_arr)

Output :

 Input array: [`1 000 2` `a1000`` 1234 ab`] Output array: [False False False] 

operations with empty strings | isdigit () function: StackOverflow Questions

What"s the difference between str.isdigit, isnumeric and isdecimal in python?

When I run these methods

s.isdigit()
s.isnumeric()
s.isdecimal()

I always got as output or all True, or all False for each value of s (which is of course a string). What"s‚Äã the difference between the three? Can you provide an example that gives two Trues and one False (or vice versa)?

Answer #1

It"s mostly about unicode classifications. Here"s some examples to show discrepancies:

>>> def spam(s):
...     for attr in "isnumeric", "isdecimal", "isdigit":
...         print(attr, getattr(s, attr)())
...         
>>> spam("¬Ω")
isnumeric True
isdecimal False
isdigit False
>>> spam("³")
isnumeric True
isdecimal False
isdigit True

Specific behaviour is in the official docs here.

Script to find all of them:

import sys
import unicodedata
from collections import defaultdict

d = defaultdict(list)
for i in range(sys.maxunicode + 1):
    s = chr(i)
    t = s.isnumeric(), s.isdecimal(), s.isdigit()
    if len(set(t)) == 2:
        try:
            name = unicodedata.name(s)
        except ValueError:
            name = f"codepoint{i}"
        print(s, name)
        d[t].append(s)

Answer #2

If you know it will be only one number in the string, i.e "hello 12 hi", you can try filter.

For example:

In [1]: int("".join(filter(str.isdigit, "200 grams")))
Out[1]: 200
In [2]: int("".join(filter(str.isdigit, "Counters: 55")))
Out[2]: 55
In [3]: int("".join(filter(str.isdigit, "more than 23 times")))
Out[3]: 23

But be carefull !!! :

In [4]: int("".join(filter(str.isdigit, "200 grams 5")))
Out[4]: 2005

Answer #3

By definition, isdecimal() ‚äÜ isdigit() ‚äÜ isnumeric(). That is, if a string is decimal, then it"ll also be digit and numeric.

Therefore, given a string s and test it with those three methods, there"ll only be 4 types of results.

+-------------+-----------+-------------+----------------------------------+
| isdecimal() | isdigit() | isnumeric() |          Example                 |
+-------------+-----------+-------------+----------------------------------+
|    True     |    True   |    True     | "038", "੦੩੮", "０３８"           |
|  False      |    True   |    True     | "⁰³⁸", "🄀⒊⒏", "⓪③⑧"          |
|  False      |  False    |    True     | "↉⅛⅘", "ⅠⅢⅧ", "⑩⑬㊿", "壹貳參"  |
|  False      |  False    |  False      | "abc", "38.0", "-38"             |
+-------------+-----------+-------------+----------------------------------+

---

1. Some examples of characters isdecimal()==True

(thus isdigit()==True and isnumeric()==True)

"0123456789"  DIGIT ZERO~NINE
"٠١٢٣٤٥٦٧٨٩"  ARABIC-INDIC DIGIT ZERO~NINE
"०१२३४५६७८९"  DEVANAGARI DIGIT ZERO~NINE
"০১২৩৪৫৬৭৮৯"  BENGALI DIGIT ZERO~NINE
"੦੧੨੩੪੫੬੭੮੯"  GURMUKHI DIGIT ZERO~NINE
"૦૧૨૩૪૫૬૭૮૯"  GUJARATI DIGIT ZERO~NINE
"୦୧୨୩୪୫୬୭୮୯"  ORIYA DIGIT ZERO~NINE
"௦௧௨௩௪௫௬௭௮௯"  TAMIL DIGIT ZERO~NINE
"౦౧౨౩౪౫౬౭౮౯"  TELUGU DIGIT ZERO~NINE
"೦೧೨೩೪೫೬೭೮೯"  KANNADA DIGIT ZERO~NINE
"൦൧൨൩൪൫൬൭൮൯"  MALAYALAM DIGIT ZERO~NINE
"๐๑๒๓๔๕๖๗๘๙"  THAI DIGIT ZERO~NINE
"໐໑໒໓໔໕໖໗໘໙"  LAO DIGIT ZERO~NINE
"༠༡༢༣༤༥༦༧༨༩"  TIBETAN DIGIT ZERO~NINE
"·ÅÄ·ÅÅ·ÅÇ·ÅÉ·ÅÑ·ÅÖ·ÅÜ·Åá·Åà·Åâ"  MYANMAR DIGIT ZERO~NINE
"០១២៣៤៥៦៧៨៩"  KHMER DIGIT ZERO~NINE
"０１２３４５６７８９"  FULLWIDTH DIGIT ZERO~NINE
"ùüéùüèùüêùüëùüíùüìùüîùüïùüñùüó"  MATHEMATICAL BOLD DIGIT ZERO~NINE
"𝟘𝟙𝟚𝟛𝟜𝟝𝟞𝟟𝟠𝟡"  MATHEMATICAL DOUBLE-STRUCK DIGIT ZERO~NINE
"𝟢𝟣𝟤𝟥𝟦𝟧𝟨𝟩𝟪𝟫"  MATHEMATICAL SANS-SERIF DIGIT ZERO~NINE
"𝟬𝟭𝟮𝟯𝟰𝟱𝟲𝟳𝟴𝟵"  MATHEMATICAL SANS-SERIF BOLD DIGIT ZERO~NINE
"𝟶𝟷𝟸𝟹𝟺𝟻𝟼𝟽𝟾𝟿"  MATHEMATICAL MONOSPACE DIGIT ZERO~NINE

2. Some examples of characters isdecimal()==False but isdigit()==True

(thus isnumeric()==True)

"⁰¹²³⁴⁵⁶⁷⁸⁹"  SUPERSCRIPT ZERO~NINE
"‚ÇÄ‚ÇÅ‚ÇÇ‚ÇÉ‚ÇÑ‚ÇÖ‚ÇÜ‚Çá‚Çà‚Çâ"  SUBSCRIPT ZERO~NINE
"🄀⒈⒉⒊⒋⒌⒍⒎⒏⒐"  DIGIT ZERO~NINE FULL STOP
"🄁🄂🄃🄄🄅🄆🄇🄈🄉🄊"  DIGIT ZERO~NINE COMMA
"⓪①②③④⑤⑥⑦⑧⑨"  CIRCLED DIGIT ZERO~NINE
"⓿❶❷❸❹❺❻❼❽❾"  NEGATIVE CIRCLED DIGIT ZERO~NINE
"⑴⑵⑶⑷⑸⑹⑺⑻⑼"  PARENTHESIZED DIGIT ONE~NINE
"‚ûÄ‚ûÅ‚ûÇ‚ûÉ‚ûÑ‚ûÖ‚ûÜ‚ûá‚ûà"  DINGBAT CIRCLED SANS-SERIF DIGIT ONE~NINE
"⓵⓶⓷⓸⓹⓺⓻⓼⓽"  DOUBLE CIRCLED DIGIT ONE~NINE
"‚ûä‚ûã‚ûå‚ûç‚ûé‚ûè‚ûê‚ûë‚ûí"  DINGBAT NEGATIVE CIRCLED SANS-SERIF DIGIT ONE~NINE
"፩፪፫፬፭፮፯፰፱"  ETHIOPIC DIGIT ONE~NINE

3. Some examples of characters isdecimal()==False and isdigit()==False but isnumeric()==True

"½⅓¼⅕⅙⅐⅛⅑⅒⅔¾⅖⅗⅘⅚⅜⅝⅞⅟↉"  VULGAR FRACTION
"৴৵৶৷৸৹"  BENGALI CURRENCY NUMERATOR
"௰௱௲"  TAMIL NUMBER TEN, ONE HUNDRED, ONE THOUSAND
"౸౹౺౻౼౽౾"  TELUGU FRACTION DIGIT
"൰൱൲൳൴൵"  MALAYALAM NUMBER, MALAYALAM FRACTION
"༳༪༫༬༭༮༯༰༱༲"  TIBETAN DIGIT HALF ZERO~NINE
"፲፳፴፵፶፷፸፹፺፻፼"  ETHIOPIC NUMBER TEN~NINETY, HUNDRED, TEN THOUSAND
"៰៱៲៳៴៵៶៷៸៹"  KHMER SYMBOL LEK ATTAK
"ⅠⅡⅢⅣⅤⅥⅦⅧⅨⅩⅪⅫⅬⅭⅮⅯ"  ROMAN NUMERAL
"ⅰⅱⅲⅳⅴⅵⅶⅷⅸⅹⅺⅻⅼⅽⅾⅿ"  SMALL ROMAN NUMERAL
"‚ÜÄ‚ÜÅ‚ÜÇ‚ÜÖ‚ÜÜ"  ROMAN NUMERAL
"⑩⑪⑫⑬⑭⑮⑯⑰⑱⑲⑳㉑㉒㉓㉔㉕㉖㉗㉘㉙㉚㉛㉜㉝㉞㉟㊱㊲㊳㊴㊵㊶㊷㊸㊹㊺㊻㊼㊽㊾㊿"  CIRCLED NUMBER TEN~FIFTY
"„âà„ââ„âä„âã„âå„âç„âé„âè"  CIRCLED NUMBER TEN~EIGHTY ON BLACK SQUARE
"⑽⑾⑿⒀⒁⒂⒃⒄⒅⒆⒇"  PARENTHESIZED NUMBER TEN~TWENTY
"‚íë‚íí‚íì‚íî‚íï‚íñ‚íó‚íò‚íô‚íö‚íõ"  NUMBER TEN~TWENTY FULL STOP
"⓫⓬⓭⓮⓯⓰⓱⓲⓳⓴"  NEGATIVE CIRCLED NUMBER ELEVEN
"‚ìæ‚ûâ‚ùø‚ûì"  various styles of CIRCLED NUMBER TEN
"🄌"  DINGBAT NEGATIVE CIRCLED SANS-SERIF DIGIT ZERO
"„Äá"  IDEOGRAPHIC NUMBER ZERO
"〡〢〣〤〥〦〧〨〩〸〹〺"  HANGZHOU NUMERAL ONE~TEN, TWENTY, THIRTY
"„Üí„Üì„Üî„Üï"  IDEOGRAPHIC ANNOTATION ONE~FOUR MARK
"㈠㈡㈢㈣㈤㈥㈦㈧㈨㈩"  PARENTHESIZED IDEOGRAPH ONE~TEN
"㊀㊁㊂㊃㊄㊅㊆㊇㊈㊉"  CIRCLED IDEOGRAPH ONE~TEN
"一二三四五六七八九十壹貳參肆伍陸柒捌玖拾零百千萬億兆弐貮贰㒃㭍漆什㐅陌阡佰仟万亿幺兩㠪亖卄卅卌廾廿"  CJK UNIFIED IDEOGRAPH
"參拾兩零六陸什"  CJK COMPATIBILITY IDEOGRAPH
"𐄇𐄈𐄉𐄊𐄋𐄌𐄍𐄎𐄏𐄐𐄑𐄒𐄓𐄔𐄕𐄖𐄗𐄘"  AEGEAN NUMBER ONE~NINE, TEN~NINETY
"𐄙𐄚𐄛𐄜𐄝𐄞𐄟𐄠𐄡𐄢𐄣𐄤𐄥𐄦𐄧𐄨𐄩𐄪"  AEGEAN NUMBER ONE~NINE HUNDRED, ONE~NINE THOUSAND
"𐄬𐄭𐄮𐄯𐄰𐄱𐄲𐄳"  AEGEAN NUMBER TEN~NINETY THOUSAND
"𐅀𐅁𐅂𐅃𐅆𐅇𐅈𐅉𐅊𐅋𐅌𐅍𐅎𐅏𐅐𐅑𐅒𐅓𐅔𐅕𐅖𐅗𐅘𐅙𐅚𐅛𐅜𐅝𐅞𐅟𐅠𐅡𐅢𐅣𐅤𐅥𐅦𐅧𐅨𐅩𐅪𐅫𐅬𐅭𐅮𐅯𐅰𐅱𐅲𐅳𐅴"  GREEK ACROPHONIC ATTIC
"𝍠𝍡𝍢𝍣𝍤𝍥𝍦𝍧𝍨"  COUNTING ROD UNIT DIGIT ONE~NINE
"𝍩𝍪𝍫𝍬𝍭𝍮𝍯𝍰𝍱"  COUNTING ROD TENS DIGIT ONE~NINE

Answer #4

str.isdigit() should do the trick.

Examples:

str.isdigit("23") ## True
str.isdigit("abc") ## False
str.isdigit("23.4") ## False

EDIT: As @BuzzMoschetti pointed out, this way will fail for minus number (e.g, "-23"). In case your input_num can be less than 0, use re.sub(regex_search,regex_replace,contents) before applying str.isdigit(). For example:

import re
input_num = "-23"
input_num = re.sub("^-", "", input_num) ## "^" indicates to remove the first "-" only
str.isdigit(input_num) ## True

Answer #5

In case you are looking for parsing (positive, unsigned) integers instead of floats, you can use the isdigit() function for string objects.

>>> a = "03523"
>>> a.isdigit()
True
>>> b = "963spam"
>>> b.isdigit()
False

String Methods - isdigit(): Python2, Python3

There"s also something on Unicode strings, which I"m not too familiar with Unicode - Is decimal/decimal

Answer #6

with positive integers you could use .isdigit:

>>> "16".isdigit()
True

it doesn"t work with negative integers though. suppose you could try the following:

>>> s = "-17"
>>> s.startswith("-") and s[1:].isdigit()
True

it won"t work with "16.0" format, which is similar to int casting in this sense.

edit:

def check_int(s):
    if s[0] in ("-", "+"):
        return s[1:].isdigit()
    return s.isdigit()

Answer #7

If you only want to extract only positive integers, try the following:

>>> txt = "h3110 23 cat 444.4 rabbit 11 2 dog"
>>> [int(s) for s in txt.split() if s.isdigit()]
[23, 11, 2]

I would argue that this is better than the regex example because you don"t need another module and it"s more readable because you don"t need to parse (and learn) the regex mini-language.

This will not recognize floats, negative integers, or integers in hexadecimal format. If you can"t accept these limitations, jmnas"s answer below will do the trick.

Answer #8

You can use any function, with the str.isdigit function, like this

>>> def has_numbers(inputString):
...     return any(char.isdigit() for char in inputString)
... 
>>> has_numbers("I own 1 dog")
True
>>> has_numbers("I own no dog")
False

Alternatively you can use a Regular Expression, like this

>>> import re
>>> def has_numbers(inputString):
...     return bool(re.search(r"d", inputString))
... 
>>> has_numbers("I own 1 dog")
True
>>> has_numbers("I own no dog")
False

Answer #9

Perhaps you are looking for human sorting (also known as natural sorting):

import re

def atoi(text):
    return int(text) if text.isdigit() else text

def natural_keys(text):
    """
    alist.sort(key=natural_keys) sorts in human order
    http://nedbatchelder.com/blog/200712/human_sorting.html
    (See Toothy"s implementation in the comments)
    """
    return [ atoi(c) for c in re.split(r"(d+)", text) ]

alist=[
    "something1",
    "something12",
    "something17",
    "something2",
    "something25",
    "something29"]

alist.sort(key=natural_keys)
print(alist)

yields

["something1", "something2", "something12", "something17", "something25", "something29"]

PS. I"ve changed my answer to use Toothy"s implementation of natural sorting (posted in the comments here) since it is significantly faster than my original answer.

---

If you wish to sort text with floats, then you"ll need to change the regex from one that matches ints (i.e. (d+)) to a regex that matches floats:

import re

def atof(text):
    try:
        retval = float(text)
    except ValueError:
        retval = text
    return retval

def natural_keys(text):
    """
    alist.sort(key=natural_keys) sorts in human order
    http://nedbatchelder.com/blog/200712/human_sorting.html
    (See Toothy"s implementation in the comments)
    float regex comes from https://stackoverflow.com/a/12643073/190597
    """
    return [ atof(c) for c in re.split(r"[+-]?([0-9]+(?:[.][0-9]*)?|[.][0-9]+)", text) ]

alist=[
    "something1",
    "something2",
    "something1.0",
    "something1.25",
    "something1.105"]

alist.sort(key=natural_keys)
print(alist)

yields

["something1", "something1.0", "something1.105", "something1.25", "something2"]

Answer #10

You"ll want to use the isdigit method on your str object:

if len(isbn) == 10 and isbn.isdigit():

From the isdigit documentation:

str.isdigit()

Return True if all characters in the string are digits and there is at least one character, False otherwise. Digits include decimal characters and digits that need special handling, such as the compatibility superscript digits. This covers digits which cannot be used to form numbers in base 10, like the Kharosthi numbers. Formally, a digit is a character that has the property value Numeric_Type=Digit or Numeric_Type=Decimal.