numpy.any () in Python

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About:
numpy.any (a, axis = None, out = None, keepdims = class numpy._globals._NoValue at 0x40ba726c): checks whether any element in the array along the specified axis is True.
Parameters:

  array:  [array_like] Input array or object whose elements, we need to test.  axis:  [int or tuple of ints, optional] Axis along which array elements are evaluated. The default (axis = None) is to perform a logical AND over all the dimensions of the input array. Axis may be negative, in which case it counts from the last to the first axis.  out:  [ndarray, optional] Output array with same dimensions as Input array, placed with result  keepdmis:  [boolean, optional] If this is set to True, the axes which are reduced are left in the result as dimensions with size one. With this option, the result will broadcast correctly against the input array. If the default value is passed, then keepdims will not be passed through to the all method of sub-classes of ndarray, however any non-default value will be. If the sub-classes sum method does not implement keepdims any exceptions will be raised. 

Return:

 A new Boolean array as per ’out’ parameter 

Code 1:

# Python program illustrating
# numpy.any () method

import numpy as geek


# Axis = NULL
# True False
# True true
# True: False = True (OR)

print ( "Bool Value with axis = NONE :" , geek. any ([[ True , False ], [ True , True ]]))


# Axis = 0
# True False
# True true
# True: False

print ( "Bool Value with axis = 0 :" , geek. any ([[ True , False ], [ True , True ]], axis = 0 ))

print ( " Bool: " , geek. any ([ - 1 , 4 , 5 ]))


# Not a number (NaN) , positive infinity and negative infinity
# evaluate to True because they are not zero.

print ( " Bool: " , geek. any ([ 1.0 , geek.nan]))

print ( "Bool Value:" , geek. any ([[ 0 , 0 ], [ 0 , 0 ]]))

Output:

 Bool Value with axis = NONE: True Bool Value with axis = 0: [True True] Bool: True Bool: True Bool Value: False 

Code 2:

# Python program illustrating
# numpy.any () method


# Parameter: keepdmis

import numpy as geek


# setting keepdmis = True

print ( " Bool Value: " , geek. any ([[ 1 , 0 ], [ 0 , 4 ]], True ))


# setting keepdmis = True

print ( "Bool Value:" , geek. any ([[ 0 , 0 ], [ 0 , 0 ]], False ))

Output:

 Bool Value: [True True] Bool Value: [False False] VisibleDeprecationWarning: using a boolean instead of an integer will result in an error in the future return umr_any (a, axis, dtype, out, keepdims) 

Links:
https://docs .scipy.org / doc / numpy-dev / reference / generated / numpy.any.html # numpy.any

Notes:
These codes will not work for online ID. Please run them on your systems to see how they work.
,
This article is provided by Mohit Gupta_OMG

numpy.any () in Python log: Questions

log

Python"s equivalent of && (logical-and) in an if-statement

5 answers

delete By delete

Here"s my code:

def front_back(a, b):
  # +++your code here+++
  if len(a) % 2 == 0 && len(b) % 2 == 0:
    return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] 
  else:
    #todo! Not yet done. :P
  return

I"m getting an error in the IF conditional.
What am I doing wrong?

934

Answer #1

You would want and instead of &&.

934

Answer #2

Python uses and and or conditionals.

i.e.

if foo == "abc" and bar == "bac" or zoo == "123":
  # do something

log

How do you get the logical xor of two variables in Python?

5 answers

Zach Hirsch By Zach Hirsch

How do you get the logical xor of two variables in Python?

For example, I have two variables that I expect to be strings. I want to test that only one of them contains a True value (is not None or the empty string):

str1 = raw_input("Enter string one:")
str2 = raw_input("Enter string two:")
if logical_xor(str1, str2):
    print "ok"
else:
    print "bad"

The ^ operator seems to be bitwise, and not defined on all objects:

>>> 1 ^ 1
0
>>> 2 ^ 1
3
>>> "abc" ^ ""
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for ^: "str" and "str"
794

Answer #1

If you"re already normalizing the inputs to booleans, then != is xor.

bool(a) != bool(b)

numpy.any () in Python NumPy: Questions

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